Question

用户最初需要选择选项“a”来添加最终放置衣服的衣柜位置。他们的信息被放入arraylist而不会被覆盖。这部分有效。

然后他们可以选择选项b，在那里它根据楼层号搜索arraylist的位置。如果找到楼层号，则用户输入装备类型，然后将其发送到Location类中的arraylist。这就是我被困住的地方。它似乎将它添加到arraylist，但是如果我想回去为该楼层号的衣柜位置添加另一套装，它会覆盖它而不是添加它。

我需要它能够将用户的装备添加到arraylist并允许用户返回，为选项b输入相同的楼层编号，并添加另外的装备以及添加的初始装备（并且不覆盖）。

我的代码如下。

主要方法：

public class Main {
    public static void main(String[] args) {
                        int selection;
    Scanner console = new Scanner(System.in);
    String firstInput;
    int floorNumber;
    String roomLocation;
    boolean loop;
    boolean bigLoop;
    ArrayList<Location> locationArr = new ArrayList<Location>();   

do{
bigLoop = true;
do{

loop = true;
    System.out.println("Select from the following:");
    System.out.println("a. Add wardrobe location");
    System.out.println("b. Add outfit to the wardrobe location");
    firstInput = console.nextLine();

    if (firstInput.equals("a")) {
            System.out.println("Please enter which floor your wardrobe is located on:");
            floorNumber = console.nextInt();
            console.nextLine();
            System.out.println("Please enter room your wardrobe is located in (e.g. living room, bedroom, etc.):");
            roomLocation = console.nextLine();  
            Location currLocation = new Location(floorNumber, roomLocation);    
            locationArr.add(currLocation);
            }
    if (firstInput.equals("b")){
       loop = false;}      
} while (loop == true);

do {
loop = true;
String outfitType;
System.out.println("Please enter the floor number:");
floorNumber = console.nextInt();
console.nextLine();
for (int i = 0; i < locationArr.size(); i++){
           if (locationArr.get(i).getFloorNumber() == floorNumber) {
               Location currLocation = new Location(locationArr.get(i).getFloorNumber(),locationArr.get(i).getRoomLocation());
               i = locationArr.size();
               System.out.println("Please enter the type of outfit to put in the wardrobe (e.g. dress, suit, etc.):");
               outfitType = console.nextLine();
               String newOutfit = outfitType;
               currLocation.addOutfit(newOutfit);
               loop = false;
            }
}
} while (loop == true);
    } while (bigLoop == true);
    }
}

位置等级

public class Location {
private final int flooorNumber;
private final String rooomLocation;
private final ArrayList<String> clothesInWardrobe = new ArrayList<String>();

public Location(int floorNumber, String roomLocation) {
     this.flooorNumber = floorNumber;
     this.rooomLocation = roomLocation;
}
    public int getFloorNumber(){
        return flooorNumber;
}
    public String getRoomLocation(){
        return rooomLocation;
}
    public int addOutfit(String outfit){
        clothesInWardrobe.add(outfit);
        //the next two lines just test to see if it adds to or overwrites the arraylist
        for (String testToSeeIfItWorks : clothesInWardrobe) {
        System.out.println("In Wardrobe = " + testToSeeIfItWorks);}
        return clothesInWardrobe.size();
    }
}

Answer 1

您的问题是您正在i位置创建位置的新实例。

           Location currLocation = new Location(locationArr.get(i).getFloorNumber(),locationArr.get(i).getroomLocation(),locationArr.get(i).getWardrobeLocation());

由于您没有将旧衣柜传递到该位置，因此正在创建衣柜的新ArrayList。您应该使用现有位置而不是创建新位置。

Location currLocation = locationArr.get(i);

调用方法添加到ArrayList

1 个答案: