Question

我有ff。查询以在Director的层次结构下显示任何人：

 WITH RECURSIVE emptree AS (
         SELECT e.win_id,
            e.full_name,
            e.current_sup_name,
            e.sbu,
            e.cost_center,
            e.lob,
            0 AS depth
           FROM app_reports.vw_hiearchy e
          WHERE e.win_id = xxxxxxx AND e.attrition_date IS NULL
        UNION ALL
         SELECT e.win_id,
            e.full_name,
            e.current_sup_name,
            e.sbu,
            e.cost_center,
            e.lob,
            t.depth + 1 AS depth
           FROM app_reports.vw_hiearchy e
             JOIN emptree t ON t.win_id = e.current_sup_win
          WHERE e.attrition_date IS NULL
        )
 SELECT emptree.win_id,
    emptree.full_name,
    emptree.current_sup_name,
    emptree.sbu,
    emptree.cost_center,
    emptree.lob,
    emptree.depth
   FROM emptree;

它工作正常，直到我被要求添加另一列（或更多）来显示谁是特定主管的主管（技术上动态地添加列 - 如果可能的话，从下到上显示所有主管）。我不确定它是否涉及为了让我实际从底部向上获取层次结构并将其显示为current_sup_name_2，current_sup_name3等等。但我不确定如何。

预先感谢任何建议。：）

Answer 1

应该可以在单个字段中显示主管的完整层次结构，并对现有查询进行少量修改：

WITH RECURSIVE emptree AS (
         SELECT e.win_id,
            e.full_name,
            e.current_sup_name,
            e.sbu,
            e.cost_center,
            e.lob,
            0 AS depth
           FROM app_reports.vw_hiearchy e
          WHERE e.win_id = xxxxxxx AND e.attrition_date IS NULL
        UNION ALL
         SELECT e.win_id,
            e.full_name,
            concat_ws(',', e.current_sup_name, t.current_sup_name) current_sup_name,
            e.sbu,
            e.cost_center,
            e.lob,
            t.depth + 1 AS depth
           FROM app_reports.vw_hiearchy e
             JOIN emptree t ON t.win_id = e.current_sup_win
          WHERE e.attrition_date IS NULL
        )
 SELECT emptree.win_id,
    emptree.full_name,
    emptree.current_sup_name,
    emptree.sbu,
    emptree.cost_center,
    emptree.lob,
    emptree.depth
   FROM emptree;

反转'With Recursive'语句

1 个答案: