在csv文件中循环

时间:2016-02-22 12:14:48

标签: java loops csv

我之前问过这个问题但是我得不到我期望的答案。因此我打开了这个新问题。

我的尝试:

    String fileName = "placements.csv";
        try {
          // Assume default encoding.
          FileWriter fileWriter = new FileWriter(fileName);

          // Always wrap FileWriter in BufferedWriter.
          BufferedWriter bufferedWriter = new BufferedWriter(fileWriter);
          // First row, write the head of the csv file.
          bufferedWriter.write(FILE_HEADER);
          bufferedWriter.newLine();
          // Increase the begin date 1 seconds until test end date.
          int seconds = 0;
          Calendar cal = Calendar.getInstance();
          cal.setTime(beginDate);
          for (int j = 0; j < convertedDifference; j++) {
            for (Job currentJob : NEHCalculator.sequenceOrderListofJobs()) {

              int times = (int) ((convertedDifference / currentJob.getInterval()) * testDevices());

              for (int i = 0; i < currentJob.getNeededTestTime() * times; i++) {

                cal.add(Calendar.SECOND, 1);
                beginDate.getTime();
                // write the test date
                bufferedWriter.write(String.valueOf(cal.getTime()));
                bufferedWriter.write(";");
                bufferedWriter.write(String.valueOf(seconds));
                bufferedWriter.write(";");
                bufferedWriter.write(currentJob.getJobname());
                bufferedWriter.write(";");
                bufferedWriter.newLine();
              }// end of currentjob loop
              seconds++;
            }// end first for loop
          }
          bufferedWriter.close();// Always close files.

        } catch (IOException ex) {
          System.out.println("Error writing to file '" + fileName);
        }  
}

首先进行循环for (int j = 0; j < convertedDifference; j++):我将程序限制在测试结束日期之前。如果我进入1小时的测试时间,我希望看到0到3599秒。

循环for (Job currentJob : NEHCalculator.sequenceOrderListofJobs())的第二个:我想测试列表中的每个设备。

对于第三个for循环for (int i = 0; i < currentJob.getNeededTestTime() * times; i++):我希望测试第一个作业currentJob.getNeededTestTime() * times times

例如,我有1小时的测试时间和第一个工作的间隔是15分钟,它测试2个设备并测试所需的时间2秒。所以输出必须是:

Mon Feb 22 12:59:59 CET 2016;0;WAF5-H;
Mon Feb 22 13:00:00 CET 2016;1;WAF5-H;
Mon Feb 22 13:00:01 CET 2016;2;WAF5-H;
Mon Feb 22 13:00:02 CET 2016;3;WAF5-H;
Mon Feb 22 13:00:03 CET 2016;4;WAF5-H;
Mon Feb 22 13:00:04 CET 2016;5;WAF5-H;
Mon Feb 22 13:00:05 CET 2016;6;WAF5-H;
Mon Feb 22 13:00:06 CET 2016;7;WAF5-H;
Mon Feb 22 13:00:07 CET 2016;8;WAF5-H;
Mon Feb 22 13:00:08 CET 2016;9;WAF5-H;
Mon Feb 22 13:00:09 CET 2016;10;WAF5-H;
Mon Feb 22 13:00:10 CET 2016;11;WAF5-H; 
Mon Feb 22 13:00:11 CET 2016;12;WAF5-H; 
Mon Feb 22 13:00:12 CET 2016;13;WAF5-H; 
Mon Feb 22 13:00:13 CET 2016;14;WAF5-H; 
Mon Feb 22 13:00:14 CET 2016;15;WAF5-H; then it will continue with second job until end of the job list.

然而,我的代码输出是:

Mon Feb 22 12:59:59 CET 2016;0;WAF5-H;
Mon Feb 22 13:00:00 CET 2016;0;WAF5-H;
Mon Feb 22 13:00:01 CET 2016;0;WAF5-H;
Mon Feb 22 13:00:02 CET 2016;0;WAF5-H;
Mon Feb 22 13:00:03 CET 2016;0;WAF5-H;
Mon Feb 22 13:00:04 CET 2016;2;WAF5-H;
Mon Feb 22 13:00:05 CET 2016;2;WAF5-H;
Mon Feb 22 13:00:06 CET 2016;2;WAF5-H;
Mon Feb 22 13:00:07 CET 2016;2;WAF5-H;
Mon Feb 22 13:00:08 CET 2016;2;WAF5-H; until Mon Feb 22 17:55:08 CET 2016;7082;WAF5-H;

这是完全错误的,我花了很多时间,但我没有完成这项任务。有人可以帮助我。

致以最诚挚的问候,

1 个答案:

答案 0 :(得分:1)

如何更改此代码

bufferedWriter.write(String.valueOf(seconds));

这个:

bufferedWriter.write(String.valueOf(cal.get(Calendar.SECOND)));

我认为它可能有效