我试图创建一个PIVOT TSQL语句,按日期和州/省总计产品,并提供AVG Transit Time。以下是我到目前为止的情况:
select *
from (select createdate [Date Processed],
stateprovince as [Province],
count(*) as [Total],
avg(datediff(day,createdate,t.eventdate)) as [AVG Delivery],
product
from recipient C left outer join
(select delivid, product, eventdesc, eventdate, eventcode
from deliverystatus
where delivid in (select max(deliv_id)
from deliverystatus
where eventcode = 'DELIVERED'
group by product)) as t ON c.product = t.product
where account = 3519 and consol <>'' and trknum <> '' and C.createdate between '2/4/2016' and '2/4/2016'
group by C.createdate, c.stateprovince, c.product
) as Q
pivot (
count(product)
for [Province] in (NY, IL, GA)
) as PVT
我的结果是:
Date Processed Total AVG Transit NY IL GA
2016-02-04 00:00:00.000 1 8 0 0 1
2016-02-04 00:00:00.000 1 11 2 4 1
2016-02-04 00:00:00.000 1 12 0 0 0
2016-02-04 00:00:00.000 1 15 0 0 0
我需要结果:
Date Processed Total AVG Transit NY IL GA
2016-02-04 00:00:00.000 8 11.5 2 4 2
最终目标是让州/省列出的AVG Transit如下:
Date Processed Total Total AVG NY AVG IL AVG GA AVG
2016-02-04 00:00:00.000 8 11.5 2 8 4 11 2 15
提前致谢。
答案 0 :(得分:0)
您需要在数据透视后添加GROUP BY
子句,并为每个输出列获取AVG
SUM
或MAX
值:
select [Date Processed], SUM(NY+IL+GA) AS [Total], AVG([AVG Delivery]) AS [AVG Delivery], SUM(NY) AS NY, SUM(IL) AS IL, SUM(GA) AS GA
from (select createdate [Date Processed],
stateprovince as [Province],
count(*) as [Total],
avg(datediff(day,createdate,t.eventdate)) as [AVG Delivery],
product
from recipient C left outer join
(select delivid, product, eventdesc, eventdate, eventcode
from deliverystatus
where delivid in (select max(deliv_id)
from deliverystatus
where eventcode = 'DELIVERED'
group by product)) as t ON c.product = t.product
where account = 3519 and consol <>'' and trknum <> '' and C.createdate between '2/4/2016' and '2/4/2016'
group by C.createdate, c.stateprovince, c.product
) as Q
pivot (
count(product)
for [Province] in (NY, IL, GA)
) as PVT
group by [Date Processed]