我目前正在尝试使用Google表格根据从我的MYSQL数据库提取的信息生成报告。
问题是有5个标题值:['Call Disposition', 'Answered', 'Busy', 'No Answer','Failed']
但问题是从数据库中提取的数据几乎会有4个值中的3个,这将定义我的Google图表标题,原因是如果"失败"找到并且只有一个值我从Google图表中收到以下错误:Uncaught Error: Row 0 has 4 columns, but must have 5
为了清楚地了解数据库,根据呼叫发生的情况自动插入值,而不是所有呼叫都会失败。
只有少数实例会使值失败,所以我正在尝试开发一种方法,如果找不到特定数字,那么添加额外的数组。
例如,这就是它当前基于从数据库中拉出来并推入MD阵列的方式:
[ [ 'ANSWERED', '477', 728 ],
[ 'BUSY', '477', 48 ],
[ 'NO ANSWER', '477', 277 ],
[ 'ANSWERED', '488', 953 ],
[ 'BUSY', '488', 9 ],
[ 'FAILED', '488', 1 ],
[ 'NO ANSWER', '488', 126 ] ]
因此,如果说没有数字没有失败处理的数字,请添加它,但是如果没有找到每个数字,则将值设置为0:
[ [ 'ANSWERED', '477', 728 ],
[ 'BUSY', '477', 48 ],
[ 'FAILED', '477', 0 ],
[ 'NO ANSWER', '477', 277 ],
[ 'ANSWERED', '488', 953 ],
[ 'BUSY', '488', 9 ],
[ 'FAILED', '488', 1 ],
[ 'NO ANSWER', '488', 126 ] ]
我现在的代码如下:
function SQLReportAgentCalls() {
valueArr = [];
connection2.query({
sql : 'select disposition, src, COUNT(*) from cdr WHERE src="477" or src="488" GROUP BY src, disposition',
timeout : 40000
}, function (error, results, rows, fields) {
console.log("-----------REPORTS------------------------");
for(i in results){
var dipo = results[i]['disposition'];
var src = results[i]['src'];
var count = results[i]['COUNT(*)'];
if(dipo === "FAILED" && count){
var chanar = new Array(dipo,src,count);
valueArr.push(chanar);
}
else if(src && count === null && dipo !== "FAILED" ){
var chanar = new Array("FAILED",src,0);
valueArr.push(chanar);
}
else{
var chanar = new Array(dipo,src,count);
valueArr.push(chanar);
}
}
console.log(valueArr);
console.log("---------------------------------------------------");
SQLReport();
});
}
生成报告的客户端代码:
//This generates the report(Google Chart) based on the information that has been pulled from the CDR table server side.
socket.on("SQL", function (valueArr) {
google.charts.load('current', {
packages : ['corechart']
});
google.charts.setOnLoadCallback(drawMaterial);
var data = valueArr;
function x(data) {
var r = [],
temp;
valueArr.forEach(function (a, i) {
if (!(i % 3)) {
temp = [a[1]];
r.push(temp);
}
temp.push(a[2]);
});
return r;
}
function drawMaterial() {
result = [['Call Disposition', 'Answered', 'Busy', 'No Answer', 'Failed']].concat(x(valueArr));
console.log(result);
var options = {
title : 'Call Disposition',
hAxis : {
title : 'Agents',
minValue : 0,
},
vAxis : {
title : 'Disposition Number'
},
isStacked : true
};
var chartdata = new google.visualization.arrayToDataTable(result);
var material = new google.visualization.ColumnChart(document.getElementById('chart'));
material.draw(chartdata, options);
}
});
这可能吗?我不确定Google Charts是否提供了自动添加值的选项(如果它们不存在),这似乎是我能想到解决问题的唯一方法。
答案 0 :(得分:0)
如果数组需要类似于此......
['Call Disposition', 'Answered', 'Busy', 'No Answer','Failed']
将SQL更改为类似的东西可能会更容易......
select
a.src,
(select count(*) from cdr where src = a.src and disposition = 'ANSWERED'),
(select count(*) from cdr where src = a.src and disposition = 'BUSY'),
(select count(*) from cdr where src = a.src and disposition = 'NO ANSWER'),
(select count(*) from cdr where src = a.src and disposition = 'FAILED')
from
cdr a
where
a.src in ("477", "488")
group by
a.src