我正在尝试从Android发布HTTP。如果我要求在LINQPAD中使用该C#代码,它可以正常工作
void Main()
{
string r = String.Format(@"<s:Body><TrackMobileApp xmlns=""soap action url"" xmlns:i=""http://www.w3.org/2001/XMLSchema-instance""><device>test</device><imei>test</imei><ipAddress>127.0.0.1</ipAddress><timeStamp>2016-02-17T17:32:00.5147663+04:00</timeStamp></TrackMobileApp></s:Body>", DateTime.Now.ToString("o"));
HttpWebRequest wr = (HttpWebRequest)HttpWebRequest.Create("URL.asmx");
wr.ProtocolVersion = HttpVersion.Version11;
wr.Headers.Add("SOAPAction", "soap action");
wr.Method = "POST";
wr.ContentType = "text/xml;charset=utf-8";
using (StreamWriter sw = new StreamWriter(wr.GetRequestStream()))
{
sw.Write(r);
}
HttpWebResponse rs = (HttpWebResponse)wr.GetResponse();
if (rs.StatusCode == HttpStatusCode.OK)
{
XmlDocument xd = new XmlDocument();
using (StreamReader sr = new StreamReader(rs.GetResponseStream()))
{
xd.LoadXml(sr.ReadToEnd());
xd.InnerXml.Dump();
}
}
}
但是从android它给了我http 415.出了什么问题?
我在onCreate
new DownloadTask().execute("URL.asmx");
我的方法是:
private class DownloadTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
//do your request in here so that you don't interrupt the UI thread
try {
return downloadContent(params[0]);
} catch (IOException e) {
return "Unable to retrieve data. URL may be invalid.";
}
}
@Override
protected void onPostExecute(String result) {
//Here you are done with the task
}
}
private String downloadContent(String myurl) throws IOException {
InputStream is = null;
int length = 500;
try {
URL url = new URL(myurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestProperty("SOAPAction", "soap action");
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/xml");
conn.setDoInput(true);
conn.connect();
int response = conn.getResponseCode();
Log.d(TAG, "The response is: " + response);
is = conn.getInputStream();
// Convert the InputStream into a string
String contentAsString = convertInputStreamToString(is, length);
return contentAsString;
} finally {
if (is != null) {
is.close();
}
}
}
public String convertInputStreamToString(InputStream stream, int length) throws IOException, UnsupportedEncodingException {
Reader reader = null;
reader = new InputStreamReader(stream, "UTF-8");
char[] buffer = new char[length];
reader.read(buffer);
return new String(buffer);
}