Question

我希望在1000到8192000之间得到随机数。随机数应该是1000,2000,3000到8192000。

以下是我尝试但未取得任何成功的代码。

ran.nextInt(8192000 - 1000)%1000;

为了获得1000,2000,3000 ......的数字，我应该改变什么？

Answer 1

最简单的方法似乎是生成1到8192之间的随机数，然后将其乘以1000：

import numpy as np
import matplotlib.pyplot as plt

class CustomCursor(object):

def __init__(self, axes, col, xlimits, ylimits, **kwargs):
    self.items = np.zeros(shape=(len(axes),3), dtype=np.object)
    self.col = col
    self.focus = 0
    i = 0
    for ax in axes:
        axis = ax
        axis.set_gid(i)
        lx = ax.axvline(ymin=ylimits[0],ymax=ylimits[1],color=col)
        ly = ax.axhline(xmin=xlimits[0],xmax=xlimits[1],color=col)
        item = list([axis,lx,ly])
        self.items[i] = item
        i += 1
def show_xy(self, event):
    if event.inaxes:
        self.focus = event.inaxes.get_gid()
        for ax in self.items[:,0]:
            self.gid = ax.get_gid()                                     
            for lx in self.items[:,1]:
                lx.set_xdata(event.xdata)
            if event.inaxes.get_gid() == self.gid:
                self.items[self.gid,2].set_ydata(event.ydata)
                self.items[self.gid,2].set_visible(True)
    plt.draw()

def hide_y(self, event):
    for ax in self.items[:,0]:
        if self.focus == ax.get_gid():
            self.items[self.focus,2].set_visible(False)




if __name__ == '__main__':
fig = plt.figure(facecolor='#07000d')
ax1 = plt.subplot2grid((2,4), (0,0), rowspan=1,colspan=4, axisbg='#aaaaaa')
ax2 = plt.subplot2grid((2,4), (1,0), rowspan=1,colspan=4, axisbg='#aaaaaa')

cc = CustomCursor([ax1,ax2], col='red', xlimits=[0,100], ylimits=[0,100], markersize=30,)
fig.canvas.mpl_connect('motion_notify_event', cc.show_xy)
fig.canvas.mpl_connect('axes_leave_event', cc.hide_y)


plt.tight_layout()
plt.show()

Answer 2

如果你想要8192000包括试试：

Random random = new Random();
for (int i = 0; i < 10; i++) {
  System.out.println((random.nextInt(8192) + 1) * 1000);
}

在这里你得到的值：1000,2000，...，8192000

在java中出现随机数生成，其中包含多个1000的数字

2 个答案: