Question

鉴于两个列表todays_ids和baseline_ids，我将使用以下内容来编译它们之间的差异：

    # Status                     added_ids             removed_ids
    # No IDs removed, none added []                    []
    # IDs removed, none added    []                    [id1, id2, ..]
    # IDs added, IDs removed     [id1, id2, ..]        [id1, id2, ..]
    # IDs added, none removed    [id1, id2, ..]        []

    added_ids = [_id for id in todays_ids if _id not in baseline_ids]
    removed_ids = [_id for id in baseline_ids if _id not in todays_ids]

然后我需要采取不同的行动，具体取决于任何给定执行的四种可能结果中的哪一种。为简单起见，让我们想象一下，我需要在每种情况下打印所有相关的ID。

if len(added_ids) == 0 and len(removed_ids) > 0
   print 'No new ids'
   print 'The following ids were removed_ids:'
   for _id in removed_ids:
       print _id 

elif len(added_ids) > 0 and len(removed_ids) > 0
   print 'The following ids were added:'
   for _id in added_ids:
       print _id 
   print 'The following ids were removed:'
   for _id in removed_ids:
       print _id 

elif len(added_ids) > 0 and len(removed_ids) == 0
   print 'The following ids were added:'
   for _id in added_ids:
       print _id 
   print 'No ids removed'

else:
    print 'No ids added or removed'

显然，这里有一些重复的工作（可能在设置带有列表理解的差异，后续逻辑中的和），以及不必要的。如何改进？

Answer 1

如果长度的总和都是0，那么这样说;否则对于每个列表，说它是空的或列出其内容。

Answer 2

试试这个：

today_ids = ['id1', 'id2', 'id5']
base_line_ids = ['id1','id2','id3','id4']

added_ids = set(today_ids).difference(base_line_ids)
removed_ids = set(base_line_ids).difference(today_ids)

# specific message for: no added, no removed
if set(today_ids) == set(base_line_ids):
    print('No ids added or removed')
    exit(0)

if len(removed_ids):
    print('The following ids were removed:\n{}'.format('\n'.join(removed_ids)))
else:
    print('No ids removed')

if len(added_ids):
    print('The following ids were added:\n{}'.format('\n'.join(added_ids)))
else:
    print('No ids added')

输出：

The following ids were removed:
id4
id3
The following ids were added:
id5

Answer 3

added_ids = set(today_ids).difference(set(baseline_ids))
removed_ids = set(baseline_ids).difference(set(today_ids))

if added_ids:
    if removed_ids:
        do_something
    else:
        do_something
else:
    if removed_ids:
        do_something
    else:
        do_something

处理两个列表之间差异的各种排列

3 个答案: