Question

我有两个浮点数变量，我希望除法作为整数返回。我尝试了一些东西，例如Math.Round（）并将它乘以1，然后除以1，我似乎无法使它工作。

  import java.util.Scanner;

  public class Calculator
  {
     public static void main (String[] args)
     {

        float firstNumber;
        float secondNumber;
        char operator;
        float answer;
        float answerRemainder;
        Scanner input = new Scanner (System.in);


        System.out.print("Enter your first number");
        firstNumber = input.nextInt();
        System.out.print("Enter the operator (s for subtraction, a for addition, m for multiplication, d for division, r for division with a remainder))\n");
        operator = input.next().charAt(0);
        while (operator != 's' && operator != 'a' && operator != 'm' && operator != 'd' && operator != 'r')

        {
           System.out.print("\nYou have entered an incorrect character. Enter the operator (s for subtraction, a for addition, m for multiplication, d for division, r for division with a remainder)\n");
           operator = input.next().charAt(0);
        }

        System.out.print("Enter your second number");
        secondNumber = input.nextInt();

        if (operator == 's')

        {
           System.out.print(firstNumber +" - "+secondNumber+" = "+(firstNumber - secondNumber));
        }

        else if (operator == 'a')

        {
           System.out.print(firstNumber +" + "+secondNumber+" = "+(firstNumber + secondNumber));
        }

        else if (operator == 'm')

        {
           System.out.print(firstNumber+" * "+secondNumber+" = "+(firstNumber * secondNumber));
        }      

        else if (operator == 'd')

        {
           System.out.print(firstNumber+" / "+secondNumber+" = "+(firstNumber / secondNumber));
        }

        else if (operator == 'r')

        {
            answerRemainder = (firstNumber / secondNumber);
            System.out.print(firstNumber+" / "+secondNumber+" = "+(answerRemainder)+" with a remainder of "+(firstNumber % secondNumber));
        }
     }
  }

所以我想要最后一行＆＃34; answerRemainder＆＃34;是一个整数

Answer 1

您可以将您的部门转为int，如answerRemainder = (int) (firstNumber / secondNumber);

然而，正如问题评论所指出的那样，做到这一点会导致精确度下降。

如果没有任何演员，firstNumber = 3.4f和secondNumber = 1.2f，firstNumber / secondNumber的结果将为2.8333333。

使用强制转换，结果为2.0，因为int是一个没有精度的数字，结果被截断并且精度被丢弃。

使用ceiling（Math.ceil）向上舍入结果，结果将向上舍入，您将获得之后的整数 2.8333333，3.0。

使用floor（Math.floor）向下舍入结果，结果将向下舍入，您将获得之前的整数 2.8333333，2.0。

注意：两个变量上的f＆＃39;值是必要的，因为没有它，默认情况下，Java会将值解释为double。

Answer 2

Float  float_variable = (float) fistNumber/(float) secondNumber;

  answerRemainder =  Math.round(float_variable);

如何划分两个浮点数并得到一个整数

2 个答案: