Question

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main (void) {
    int n, i, input_cases,x;
    scanf("%d", &input_cases);
    float *results = malloc(input_cases*sizeof(float));

    for (x=0; x<input_cases; x++){
    float num[100], sum[2] = {0.0}, average[2] = {0.0};
    printf("Enter the total amount of numbers: ");
    if (scanf("%d", &n) != 1) {  /* validates input */
        fprintf (stderr, "error: invalid input.\n");
        return 1;
    }
    for (i = 0; i < n; i++) {
        if (scanf("%f", &num[i]) != 1) { /* validate input */
            fprintf (stderr, "error: invalid input.\n");
            return 1;
        }
    }
    /* sum/average 1st-half */
    for (i = 0; i < n/2; ++i){
        sum[0] += num[i];
        average[0] = sum[0] * 2 / n;
    }
    /* sum/average 2nd-half */
    for (i = n/2; i < n; ++i){
        sum[1] += num[i];
        average[1] = sum[1] * 2 / n;
    }
    if (average[0]>average[1]){
            results[x]=average[0];
            printf("%.6f\n", average[0]);
    }
    else{
            results[x]=average[1];
            printf("%.6f\n", average[1]);}
    }
    for (x=0; x<input_cases; x++){
        printf("%.6f\n", results[x]);
        free(results);
    }
    return 0;
}

这就是我的代码所做的：

Input:  
2  
Enter the total amount of numbers: 10  
10  
8  
9  
15  
12  
2  
3  
8  
7  
11  
10.800000(This is the output)  
Enter the total amount of numbers: 4  
3  
3  
2  
1  
3.000000(This is the output)
10.800000(My output when i dynamically allocate an array to display everything at the end)  
0.000000(My output when i dynamically allocate an array to display everything at the end)

这就是我实际想要它的样子：

Input:  
2  
Enter the total amount of numbers: 10  
10  
8  
9  
15  
12  
2  
3  
8  
7  
11  
Enter the total amount of numbers: 4  
3  
3   
2  
1  

Output:  
10.800000  
3.000000

我怎样才能从计算中得到我最后输出的所有内容，而不是在每次计算结束时分别输出每一项？

Answer 1

打印完所有值后，您应public class MyActivity extends Activity { private static final int PROGRESS = 0x1; private ProgressBar mProgress; private int mProgressStatus = 0; private Handler mHandler = new Handler(); protected void onCreate(Bundle icicle) { super.onCreate(icicle); setContentView(R.layout.progressbar_activity); mProgress = (ProgressBar) findViewById(R.id.progress_bar); // Start lengthy operation in a background thread new Thread(new Runnable() { public void run() { while (mProgressStatus < 100) { mProgressStatus = doWork(); // Update the progress bar mHandler.post(new Runnable() { public void run() { mProgress.setProgress(mProgressStatus); } }); } } }).start(); } } free。但是你在打印第一个值后array犯了free这个错误。我认为你明白了。

array

如何在结束时一次性输出结果，而不是在使用for循环时逐个输出结果？

1 个答案: