选择多行

Question

如果他们的id等于1，我想取一个字段的所有成员。

数据库：

问题在于，当我尝试拍摄所有的光目录时，我只得到第一个光目录，另外两个没有。

错误：

代码：

<?php

$yui1 = "SELECT photodirectory FROM photos WHERE photoowner='" . $userid . "'";
$rquery1 = mysqli_query($connDirectory, $yui1);
echo "rquery1 is equal to: "; 
var_dump($rquery1);
echo "</br>";

if($fotoutente = mysqli_fetch_row($rquery1)){ //fotoutente = userphoto

	for($c = 0; $c < count($fotoutente); $c++){
		echo '<img src="../' . $fotoutente["{$c}"] . '">' . "</br>";

    }
	
	echo "fotoutente is equal to: ";
	var_dump($fotoutente);
	
}
?>

如果他们的id是1，我怎么能把所有的photodirectory成员带走？ 无论如何，上面的PHP代码是用于创建一个包含所有目录的photodirectory的数组，如果等等等...

请救我和加勋爵打败playmysql4。 抱歉英语不好，但我是意大利人......

Answer 1

通过迭代mysqli_fetch_assoc循环并在结果中使用<?php $yui1 = "SELECT photodirectory FROM photos WHERE photoowner= $userid "; $result = mysqli_query($connDirectory, $yui1); echo "rquery1 is equal to: "; var_dump($result); echo "</br>"; if (mysqli_num_rows($result) > 0) { // output data of each row while($row = mysqli_fetch_assoc($result)) { echo '<img src="../' . $row["photodirectory"] . '">' . "</br>"; } } else { echo "0 results"; } ?> 来正确重做代码。

这样做：

def resolveA(implicit a: A): String => String = { prefix =>
  s"$prefix a=$a"
}

case class A(n: Int)
implicit val a = A(1)

println(resolveA("-->"))  // won't compile

Answer 2

反对SQL注入：

<?php
if (ctype_digit(strval($userid)) === false) {
    echo "UserID is not valid!";
    exit();
}
$userid_secure = bin2hex($userid);
$rquery1 = mysqli_query($connDirectory, "SELECT photodirectory FROM photos WHERE photoowner=UNHEX('$userid_secure')";

if (mysqli_num_rows($rquery1) > 0) {
    while ($fotoutente = mysqli_fetch_assoc($rquery1)) {
        echo '<img src="../'.$fotoutente["photodirectory"].'"></br>';
    }
} else {
    echo "No results";
}
?>