我正在设计一个可以通过GUI访问的数据库,我有三个类Main,Database和GUI,当我运行main时出现错误,GUI关闭,然后是一条简短的错误消息,我无法读取,不知道这是哪里出错,因为我认为这可能是一些问题。谢谢你的帮助:)
这是我的主要课程
public class MainApplication {
@SuppressWarnings("unused")
public static void main(String[] args) {
VideoStoreGUI window = new VideoStoreGUI();
}
}
我的数据库类:
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.Scanner;
import javax.swing.JOptionPane;
@SuppressWarnings("unused")
public class DataBase {
static Connection con = null;
static Statement stmt = null;
static ResultSet rs = null;
static Scanner in = new Scanner(System.in);
public void close_connection() {
try
{
con.close();
System.out.println("Database Connections Succesully Closed.");
}
catch (SQLException sqle)
{
System.out.println("Error: failed to close the database");
}
}
public static void addMember(int member_id, String name, String address) // Adding a Member to the Database.
{
try {
String str = "INSERT INTO members (member_id, name, address) values(" + member_id + ", '" + name + "', '"
+ address + "');";
int rows = stmt.executeUpdate(str);
System.out.println("Success in adding member");
} catch (SQLException sqle) {
JOptionPane.showMessageDialog(null, "Error: Could not add member");
}
}
public static void initialize_database() {
try {
Class.forName("com.mysql.jdbc.Driver");
String url = "jdbc:mysql://localhost:3306/videostore";
con = DriverManager.getConnection(url, "root", "admin");
stmt = con.createStatement();
} catch (Exception e) {
System.out.println("Error: Failed to connect to database\n" + e.getMessage());
}
}
public DataBase()
{
initialize_database();
}
}
和我的GUI类:
import java.awt.BorderLayout;
import java.awt.EventQueue;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.border.EmptyBorder;
import javax.swing.JTabbedPane;
import javax.swing.JLabel;
import javax.swing.JTextField;
import javax.swing.JButton;
import javax.swing.JMenuBar;
public class VideoStoreGUI extends JFrame {
private JFrame frame;
DataBase my_database;
private JPanel contentPane;
private JTextField textMemberID;
private JTextField textMemberName;
private JTextField textMemberAddress;
/**
* Create the frame.
*/
public VideoStoreGUI() {
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setBounds(100, 100, 450, 400);
JMenuBar menuBar = new JMenuBar();
setJMenuBar(menuBar);
contentPane = new JPanel();
contentPane.setBorder(new EmptyBorder(5, 5, 5, 5));
setContentPane(contentPane);
contentPane.setLayout(null);
JTabbedPane tabbedPane = new JTabbedPane(JTabbedPane.TOP);
tabbedPane.setBounds(10, 31, 232, 240);
contentPane.add(tabbedPane);
JPanel panel = new JPanel();
tabbedPane.addTab("Members", null, panel, null);
panel.setLayout(null);
JLabel labelMemberID = new JLabel("Members ID");
labelMemberID.setBounds(10, 11, 85, 14);
panel.add(labelMemberID);
JLabel labelMemberName = new JLabel("Members Name");
labelMemberName.setBounds(10, 36, 85, 14);
panel.add(labelMemberName);
JLabel labelMemberAddress = new JLabel("Members Address");
labelMemberAddress.setBounds(10, 61, 85, 14);
panel.add(labelMemberAddress);
textMemberID = new JTextField();
textMemberID.setBounds(131, 8, 86, 20);
panel.add(textMemberID);
textMemberID.setColumns(10);
textMemberName = new JTextField();
textMemberName.setColumns(10);
textMemberName.setBounds(131, 33, 86, 20);
panel.add(textMemberName);
textMemberAddress = new JTextField();
textMemberAddress.setColumns(10);
textMemberAddress.setBounds(131, 58, 86, 20);
panel.add(textMemberAddress);
JButton buttonAddMember = new JButton("Add Member");
buttonAddMember.setBounds(10, 86, 102, 23);
panel.add(buttonAddMember);
JButton buttonRemoveMember = new JButton("Add Member");
buttonRemoveMember.setBounds(115, 86, 102, 23);
panel.add(buttonRemoveMember);
JButton buttonSearchMember = new JButton("Add Member");
buttonSearchMember.setBounds(66, 120, 102, 23);
panel.add(buttonSearchMember);
JPanel panel_1 = new JPanel();
tabbedPane.addTab("Products", null, panel_1, null);
}
}
答案 0 :(得分:0)
我只看到一个可以弹出窗口的地方。如果您愿意,可以保留它,但添加系统输出并确保您的消息:
catch (SQLException sqle) {
System.out.writeln("Exception:"+sqle);
JOptionPane.showMessageDialog(null, "Error: Could not add member");
}
根据此消息的位置,我认为你有错误的sql或数据库。我建议你打印你的sql和它的结果。
答案 1 :(得分:0)
这对我不起作用的主要原因是因为我从GUI中删除了setVisable(true)并忘记将其添加回方法,然后我收到了错误" AWT-EventQueue-0&# 34;这与设置数据库连接的方式有关,删除并添加JDBC驱动程序再次解决了这个问题。