我对XLST很新。我已经尝试了几周将xml文件转换为纯文本文件。我想检查一个特定的属性值，并根据父节点子节点中的以下属性打印出一个值。
我尝试了不同的方法，我完全感到困惑，代码可能看起来很混乱。
以下是我正在尝试使用的xml的摘录：
func SearchC(){
let pathMC = NSBundle.mainBundle().pathForResource("myPlistArray", ofType: "plist")
let dictMC = NSDictionary(contentsOfFile: pathMC!)
myPlistArray = dictMC!["Questions"]!.mutableCopy() as? Array
if let questionArray = myPlistArray as? [[String:AnyObject]] {
let answersC = questionArray.filter({
if let correct = $0["CorrectAnswer"] as? String {
return correct.uppercaseString == "C"
}
return false
})
print("\(answersC)")
}
}
我现在的xls：
func SearchYES(){
let pathMC = NSBundle.mainBundle().pathForResource("myPlistArray", ofType: "plist")
let dictMC = NSDictionary(contentsOfFile: pathMC!)
myPlistArray = dictMC!["Questions"]!.mutableCopy() as? Array
if let questionArray = myPlistArray as? [[String:AnyObject]] {
let isFavorite = questionArray.filter({
if let favorite = $0["isFavorite"] as? String {
return favorite.uppercaseString == "YES"
}
return false
})
print("\(isFavorite)")
}
}
所以这部分我无法开始工作：
<?xml version="1.0" encoding="utf-8"?>
<LandXML xmlns="http://www.landxml.org/schema/LandXML-1.2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.landxml.org/schema/LandXML-1.2 http://www.landxml.org/schema/LandXML-1.2/LandXML-1.2.xsd" version="1.2" date="2016-02-11" time="13:38:06" readOnly="false" language="English">
<HexagonLandXML xmlns="http://xml.hexagon.com/schema/HeXML-1.7" xsi:schemaLocation="http://xml.hexagon.com/schema/HeXML-1.7 http://xml.hexagon.com/schema/HeXML-1.7.xsd" xmlns:landxml="http://www.landxml.org/schema/LandXML-1.2" averagingMode="Average" averagingMethod="Weighted" averagingPosLimit="0.050000" averagingHgtLimit="0.075000">
<Point uniqueID="100" class="measured" subclass="GPS phase" lineworkFlag="FORT" averageUsage="true" applicationNumber="11">
<Coordinates originalCoordSysKind="Ellipsoidal" originalGeodeticDatumKind="WGS84" originalHeightKind="ellipsoidal">
<WGS84>
<Cartesian x="3374756.763053" y="893574.649632" z="5320249.612556"/>
<Geodetic lat="56.904101405681359" lon="14.830552433162786" hghtE="206.861483" hghthO="174.187582"/>
</WGS84>
<Local>
<Cartesian x="3374756.763053" y="893574.649632" z="5320249.612556"/>
<Geodetic lat="56.904101406543710" lon="14.830552433162786" hghtE="206.861556" hghthO="174.187583"/>
<Grid e="139675.834002" n="6309247.502715" hghtE="206.861556" hghthO="174.187583"/>
</Local>
</Coordinates>
<PointCode code="RKO" codeDesc="" codeGroup="TRANSPORT" codeLinework="open line"></PointCode>
<PointQuality Qxx="0.0003475127" Qxy="0.0000634192" Qxz="-0.0003087937" Qyy="0.0002335805" Qyz="-0.0001324870" Qzz="0.0014808670" MeanError="1.156631" CQ3D="0.052521" CQPos="0.027882" CQHeight="0.044509"/>
</Point>
<Point uniqueID="101" class="measured" subclass="GPS phase" averageUsage="true" applicationNumber="11">
<Coordinates originalCoordSysKind="Ellipsoidal" originalGeodeticDatumKind="WGS84" originalHeightKind="ellipsoidal">
<WGS84>
<Cartesian x="3374779.920766" y="893569.513712" z="5320236.614863"/>
<Geodetic lat="56.903879154810298" lon="14.830373667852458" hghtE="207.478635" hghthO="174.804021"/>
</WGS84>
<Local>
<Cartesian x="3374779.920766" y="893569.513712" z="5320236.614863"/>
<Geodetic lat="56.903879155672669" lon="14.830373667852458" hghtE="207.478708" hghthO="174.804022"/>
<Grid e="139664.880750" n="6309222.780312" hghtE="207.478708" hghthO="174.804022"/>
</Local>
</Coordinates>
<PointCode code="EBS" codeDesc="Belysningsstolpe" codeGroup="ELLEDNING" codeLinework="none">
<Attribute name="Attribut 1" value="-5"/>
</PointCode>
<PointQuality Qxx="0.0001718767" Qxy="-0.0000094370" Qxz="0.0000030377" Qyy="0.0000956758" Qyz="-0.0000386372" Qzz="0.0007723176" MeanError="0.630108" CQ3D="0.020319" CQPos="0.010307" CQHeight="0.017511"/>
</Point>
</HexagonLandXML>
</LandXML>
简而言之，我想检查下一个Point / PointCode / @ codeLinework的值并打印出一个值。
答案 0 :(得分：0)
如果你能发布预期的结果会更好，所以我们可以提供更准确的答案。即便如此，我还是试着根据您的意见，并通过微小的改动创建了这个：
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:landxml="http://www.landxml.org/schema/LandXML-1.2"
xmlns:hexxml="http://xml.hexagon.com/schema/HeXML-1.7"
exclude-result-prefixes="xs"
version="2.0">
<xsl:template match="/">
<xsl:for-each select="landxml:LandXML/hexxml:HexagonLandXML/hexxml:Point">
<xsl:for-each select="./hexxml:PointCode">
<xsl:value-of select="string(@code)"/>
<xsl:text>,</xsl:text>
<xsl:if test="@codeLinework='open line'">
<xsl:choose>
<xsl:when test="../@lineworkFlag='START LINJE'">
<xsl:text>40</xsl:text>
<xsl:text>,</xsl:text>
</xsl:when>
<xsl:when test="../following-sibling::*[1]/hexxml:PointCode[@codeLinework='none']">
<xsl:text>41</xsl:text>
<xsl:text>,</xsl:text>
</xsl:when>
<xsl:when test="../@codeLinework">
<xsl:text> </xsl:text>
<xsl:text>,</xsl:text>
</xsl:when>
</xsl:choose>
</xsl:if>
<xsl:if test="@codeLinework='none'">
<xsl:text>30</xsl:text>
<xsl:text>,</xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
我更改了Point和PointCode的选择器，因为它们不正确，我稍微改变了你试图用来获得以下兄弟的XPath表达式。
这是我针对您的XML运行时的输出：
RKO,41,EBS,30,