Question

我试图在段落中隐藏以'＃'开头的单词。例如：

String first = "This word is #12 and #word ";

TextView t = (TextView) findViewById(R.id.textbox);
t.setText(first);

我想隐藏单词“12”和“单词”..

最欣赏

Answer 1

在FlyingPumba的回答中，如果您使用拆分（＆＃34;＆＃34;）而不是拆分（＆＃39;＆＃39;）将正常工作。还有另一种方法可以实现它。

String first = "This word is #12 and #word ";

StringTokenizer st = new StringTokenizer(first, " ");

StringBuilder sb = new StringBuilder();
while (st.hasMoreTokens()) {
    String s = st.nextToken();
    if (!s.startsWith("#")) {
        sb.append(s);
        sb.append(" ");
    }
}

TextView t = (TextView) findViewById(R.id.textbox);
t.setText(sb.toString());

Answer 2

您可以使用以下内容：

String first = "This word is #12 and #word ";
String[] words = first.split(" ");
String result = "";
for (String word : words) {
    if (!word.startsWith("#")) {
        result += word;
        result += " ";
    }
}

TextView t = (TextView) findViewById(R.id.textbox);
t.setText(result);

TextView在pargephraph中隐藏单词？

2 个答案: