Question

我正在编写一个有趣和实践的程序，它接受用户输入并猜测输入值。我不能在我的测试环境中提示，所以我使用数字5代替，我也使用debug而不是console.log。我无法找到无限循环开始的位置，据我所知它只是计算一个数组，直到它到达字符串'5'，并且应该停止循环。我需要第二双眼睛，Stack Overflow。谢谢！

//Password Cracker

//"userPassword" will not be read by the computer, instead it will be guessed and reguessed.
var userPassword = 5 + ''

//the following variable contains an array of all the possible characters that can be present.
var possibleCharacters = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','1','2','3','4','5','6','7','8','9','0'];

//the computer's current guess.
var computerGuess = null;

//establishes that the computer has not correctly guessed the password, will be changed when password is discovered.
var correctGuess = null;

//the following variable keeps track of how many guesses it takes for the computer to crack the password.
var totalGuesses = 0;

//the following function checks if the current guess of the computer matches the password inputted by the user.
var checkPassword = function(passwordGuess) {

    if(passwordGuess === userPassword) {
        debug("Your password is " + computerGuess + ". Gotta do better to fool me!");
    }else{
        debug("Guessing again.");
    };

};

//the loop that should stop when the password has been guessed correctly. the variable 'i' counts up through the strings in the array.
while(computerGuess !== userPassword) {

    for(var i = 0; i < 61; i++) {
        computerGuess = possibleCharacters[i];
        checkPassword(computerGuess);
        };
    };

end;

Answer 1

//the loop that should stop when the password has been guessed correctly. the variable 'i' counts up through the strings in the array.
while(computerGuess !== userPassword) {    
    for(var i = 0; i < 61; i++) {
        computerGuess = possibleCharacters[i];
        checkPassword(computerGuess);
    };
};

这是一个无限循环，因为内循环（for循环）总是遍历所有字符，所以computerGuess最后是'0'。因此，始终满足while条件。一旦你猜到了正确的密码，就可以通过打破for循环来解决这个问题：

while(computerGuess !== userPassword) {
    for(var i = 0; i < 61 && computerGuess !== userPassword; i++) {
        computerGuess = possibleCharacters[i];
        checkPassword(computerGuess);
    };
};

Answer 2

如果您想暴力攻击，请在此处查看此算法：

https://codereview.stackexchange.com/questions/68063/brute-force-password-cracker

或google some＆＃34; bruteforce javascript算法＆＃34;

干杯

无法在JavaScript程序

2 个答案: