如何设置上个月的最短日期26.这是我的代码。
int difference = 0;
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) {
difference = 31;
} else if (month == 4 || month == 6 || month == 9 || month == 11) {
difference = 30;
} else if (month == 2) {
if (year % 4 == 0) {
difference = 29;
} else
difference = 28;
}
int minDiffrence = 0;
if (day == 26) {
minDiffrence = difference;
} else {
minDiffrence = difference - (26 - day);
}
dpd.getDatePicker().setMinDate(System.currentTimeMillis() - 24 * 60 * 60 * 1000 * minDiffrence);
答案 0 :(得分:0)
试试这个: -
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.MONTH, calendar.get(Calendar.MONTH) - 1);
calendar.set(Calendar.DAY_OF_MONTH, 26);
dpd.getDatePicker().setMinDate(calendar.getTimeInMillis());
答案 1 :(得分:0)
此代码示例代码涵盖从日期=上个月的开始日期和结束日期=当前日期的当前日期。我认为这段代码对您有所帮助。
datePicker = (DatePicker) findViewById(R.id.datePicker);
calendar = Calendar.getInstance();
calendar.add(Calendar.MONTH, -1);
calendar.set(Calendar.DAY_OF_MONTH, 1);
datePicker.setMinDate(calendar.getTimeInMillis());
datePicker.setMaxDate(new Date().getTime());