我有一个小的二进制文件。我想将该二进制文件作为字符数组导入C程序,如下所示:
char some_binary_data[] = "\000-type or \xhh-type escape sequences and such here";
是否有标准的shell命令可以使用C风格的转义呈现二进制数据?如果我可以在八进制样式转义和十六进制转义之间进行选择,则可以获得奖励积分。
例如,如果我的文件包含字节
0000000 117000 060777 000123
0000006
,我想将其呈现为"\000\236\377a\123"
。
答案 0 :(得分:1)
根据我的知识,并没有完全像这样,但是" od"如果你在* nix世界或mac中,那就很接近了。不知道windoz。
这是一个shell脚本
#!/bin/bash
if [ ! -f "$1" ]; then
echo file "$1" does not exist
exit
fi
if [ -z $2 ]; then
echo output file not specfied
exit
fi
echo "char data[]=" > $2
od -t x1 $1 |awk '/[^ ]* *[^ ]/ {printf(" \"");for(i=2;i<=NF;++i)printf("\\x%s", $i); print "\""}' >> $2
echo " ;" >> $2
答案 1 :(得分:1)
这是我放在一起应该有用的东西:
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
#include <ctype.h>
int main(int argc, char *argv[])
{
int infile = open(argv[1], O_RDONLY);
if (infile == -1) {
perror("open failed");
exit(1);
}
FILE *outfile = fopen(argv[2],"w");
if (!outfile) {
perror("fopen failed");
exit(1);
}
fprintf(outfile, "char %s[] = ", argv[3]);
int buflen;
int totallen, i, linelen;
char buf[1000];
totallen = 0;
linelen = atoi(argv[4]);
while ((buflen=read(infile, buf, sizeof(buf))) > 0) {
for (i=0;i<buflen;i++) {
if (totallen % linelen == 0) {
fprintf(outfile, "\"");
}
if (buf[i] == '\"' || buf[i] == '\\') {
fprintf(outfile,"\\%c",buf[i]);
} else if (isalnum(buf[i]) || ispunct(buf[i]) || buf[i] == ' ') {
fprintf(outfile,"%c",buf[i]);
} else {
fprintf(outfile,"\\x%02X",buf[i]);
}
if (totallen % linelen == linelen - 1) {
fprintf(outfile, "\"\n ");
}
totallen++;
}
}
if (totallen % linelen != 0) {
fprintf(outfile, "\"");
}
fprintf(outfile, ";\n");
close(infile);
fclose(outfile);
return 0;
}
示例输入:
This is a "test". This is only a \test.
被称为:
/tmp/convert /tmp/test1 /tmp/test1.c test1 10
示例输出
char test1[] = "This is a "
"\"test\". Th"
"is is only"
"a \\test.\x0A"
;