Question

我的网站有3项服务，我希望能够点击服务1并查看菜单1，点击服务2并查看菜单2，点击服务3并查看菜单3.我有以下代码但它是没有按预期工作。当我点击服务2和服务3时，什么都没有显示出来。

HTML：

<div class="row" id="menu_service1">
    <div class="col-md-4">
        <span><h5>Choose a line</h5> <select id="lines" class="form-control"></select></span> 
        <span><h5>Choose a stop</h5> <select id="stop" class="form-control"></select></span>
    </div>
</div>

<div class="row" id="menu_service2">
    <div class="col-md-4">
        <span><h5>Choose a stop</h5> <select id="stop" class="form-control"></select></span> 
        <span><h5>Choose a stop</h5> <select id="stop" class="form-control"></select></span>
    </div>
</div>

<div class="row" id="menu_service3">
    <div class="col-md-4">
        <p>blah</p>
    </div>
</div>

JS：

$(document).ready(function() { 
    var line_array = ["Line 1", "Line 2", "Line 3"];
    var stops = ["stop1", "stop2", "stop3"] ;

    for (var i = 0; i < line_array.length; i++) {
        $('#lines').append('<option>' + line_array[i] + '</option>');
    }

    for (var i = 0; i < stops.length; i++) {
        $('#stop').append('<option>' + stops[i] + '</option>');
    }

    $('#menu_service1').hide();
    $('#menu_service2').hide();
    $('#menu_service3').hide();

    $('#Service_1').click(function() {
        $('#menu_service1').toggle();
    });

    $('#Service_2').click(function() { 
        $('#menu_service2').toggle();
    });

    $('#Service_3').click(function() { 
        $('#menu_service3').toggle();
    });
});

Answer 1

<强> Working Fiddle

id在同一文档中应该是唯一的，因此请尝试用通用类替换重复的文档，例如：

<span><h5>Choose a line</h5> <select class="form-control lines"></select></span> 
<span><h5>Choose a stop</h5> <select class="form-control stop"></select></span>

在你的JS中使用它们与类选择器点.，如：

$('.lines').append('<option>' + line_array[i] + '</option>');

您还应该通过添加ID选择器sogn #来修复以下两行中的拼写错误：

$('menu_service2').toggle();
$('menu_service2').toggle();

应该是：

$('#menu_service2').toggle();
$('#menu_service2').toggle();

此外，您可以为多个选择器使用逗号,分隔符，而不是：

$('#menu_service1').hide();
$('#menu_service2').hide();
$('#menu_service3').hide();

仅使用：

$('#menu_service1,#menu_service2,#menu_service3').hide();

希望这有帮助。

$(document).ready(function() { 
  var line_array = ["Line 1", "Line 2", "Line 3"];
  var stops = ["stop1", "stop2", "stop3"] ;

  for (var i = 0; i < line_array.length; i++) {
    $('.lines').append('<option>' + line_array[i] + '</option>');
  }

  for (var i = 0; i < stops.length; i++) {
    $('.stop').append('<option>' + stops[i] + '</option>');
  }

  $('#menu_service1,#menu_service2,#menu_service3').hide();

  $('#Service_1').click(function() {
     $('.row').hide();
     $('#menu_service1').toggle();
  });

  $('#Service_2').click(function() { 
     $('.row').hide();
     $('#menu_service2').toggle();
  });

  $('#Service_3').click(function() { 
     $('.row').hide();
     $('#menu_service3').toggle();
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<link href="https://netdna.bootstrapcdn.com/bootstrap/3.0.0/css/bootstrap.min.css" rel="stylesheet"/>
<script src="https://netdna.bootstrapcdn.com/bootstrap/3.0.0/js/bootstrap.min.js"></script>
<button id='Service_1'>Service 1</button>
<button id='Service_2'>Service 2</button>
<button id='Service_3'>Service 3</button>

<div class="row" id="menu_service1">
  <div class="col-md-4">
    <span><h5>Choose a line1</h5> <select class="form-control lines"></select></span> 
    <span><h5>Choose a stop1</h5> <select class="form-control stop"></select></span>
  </div>
</div>

<div class="row" id="menu_service2">
  <div class="col-md-4">
    <span><h5>Choose a line2</h5> <select class="form-control lines"></select></span> 
    <span><h5>Choose a stop2</h5> <select class="form-control stop"></select></span>
  </div>
</div>

<div class="row" id="menu_service3">
  <div class="col-md-4">
    <p>blah</p>
  </div>
</div>

Answer 2

您忘记了选择器中ID的前面的＃符号。

$('#menu_service2').toggle();
$('#menu_service3').toggle();

Answer 3

我更喜欢编写更少的代码行来获得相同的结果。

＆＃13;

$(function () {
  var line_array = ["Line 1", "Line 2", "Line 3"];
  var stops = ["stop1", "stop2", "stop3"] ;

  for (var i = 0; i < line_array.length; i++) {
    $('[id^=lines]').append('<option>' + line_array[i] + '</option>');
  }

  for (var i = 0; i < stops.length; i++) {
    $('[id^=stop]').append('<option>' + stops[i] + '</option>');
  }

  $('[id^=menu_service]').hide();

  $('[id^=Service_]').click(function() {
    var currDiv = this.getAttribute('data-div');
    $('div.row:not(#' + currDiv + ')').hide();
    $('#' + currDiv).toggle();
  });
});

＆＃13;

<script src="http://code.jquery.com/jquery-1.11.3.min.js"></script>

<button id='Service_1' data-div="menu_service1">Service 1</button>
<button id='Service_2' data-div="menu_service2">Service 2</button>
<button id='Service_3' data-div="menu_service3">Service 3</button>
<div class="row" id="menu_service1">
    <div class="col-md-4">
        <span><h5>Choose a line</h5> <select id="lines1" class="form-control"></select></span>
        <span><h5>Choose a stop</h5> <select id="stop1" class="form-control"></select></span>
    </div>
</div>

<div class="row" id="menu_service2">
    <div class="col-md-4">
        <span><h5>Choose a stop</h5> <select id="stop2" class="form-control"></select></span>
        <span><h5>Choose a stop</h5> <select id="stop2" class="form-control"></select></span>
    </div>
</div>

<div class="row" id="menu_service3">
    <div class="col-md-4">
        <p>blah</p>
    </div>
</div>

＆＃13;

使用Javascript在div元素之间切换

3 个答案: