Question

我试图在if条件下比较来自csv文件的字符串读取。以下是我编写的示例代码：

export IFS="~"
while read a b c
do
    echo "line Num:$a"
    if [ "$b"=="sat" ];then
        echo "Its saturday"
        echo $c
    elif [ "$b"=="sun" ];then
        echo "Its sunday"
        echo $c
    else
        echo "Its weekday"
        echo $c
    fi
done < "$1"

以下是csv文件：

1~sat~enjoy
2~sun~enjoy
3~mon~work
4~tue~work
5~sun~enjoy

以下是我得到的输出：

line Num:1
Its saturday
enjoy
line Num:2
Its saturday
enjoy
line Num:3
Its saturday
enjoy
line Num:4
Its saturday
enjoy
line Num:5
Its saturday
enjoy

需要以下输出：

line Num:1
Its saturday
enjoy
line Num:2
Its sunday
enjoy
line Num:3
Its weekday
work
line Num:4
Its weekday
work
line Num:5
Its sunday
enjoy

知道如何实现这个目标吗？

Answer 1

试

export IFS="~"
while read a b c
do
echo "line Num:$a"
if [ "$b" = "sat" ];then
echo "Its saturday"
echo $c
elif [ "$b" = "sun" ];then
echo "Its sunday"
echo $c
else
echo "Its weekday"
echo $c
fi
done < "$1"

不要使用"$foo"=="$bar"，因为bash只会看到一个令牌。

您也可以尝试

case "$b" in
sat) echo "It's saturday" ;;
sun) echo "It's sunday" ;;
*) echo "It's weekday" ;;
esac
echo $c

比较从csv文件读取的字符串

1 个答案: