if (i == 1) //if dropdown #1 index > 0
{
strSelectedType = ViewState["EN"].ToString();
strSelectedCol = "Name";
}
if (i == 2) //if dropdown #2 index > 0
{
strSelectedType = ViewState["SU"].ToString();
strSelectedCol = "Super";
}
if (i == 3) //if dropdown #3 index > 0
{
strSelectedType = ViewState["DT"].ToString();
strSelectedCol = "Deran";
}
if (i == 4) //if dropdown #4 index > 0
{
strSelectedType = ViewState["PR"].ToString();
strSelectedCol = "PRate";
}
DataTable dtTest = new DataTable();
dtTest = (DataTable)ViewState["gvDataTable"];
DataTable selectedTable = dtTest.AsEnumerable()
.Where(r => r.Field<string>(strSelectedCol) == strSelectedType)
.CopyToDataTable();
以上代码仅使用一列进行过滤。
如何修改dtText.AsEnumerable()
以便它会像这样过滤:
DataTable selectedTable = dtTest.AsEnumerable()
.Where(if (dropdown #1 > 0) {r => r.Field<string>(strSelectedCol) == strSelectedType }
if (dropdown #2 > 0) { r => r.Field<string>(strSelectedCol) == strSelectedType }
if (dropdown #3 > 0) { r => r.Field<string>(strSelectedCol) == strSelectedType }
if (dropdown #4 > 0) { r => r.Field<string>(strSelectedCol) == strSelectedType })
.CopyToDataTable();
如果所选索引&gt;它将遍历每个下拉附加过滤器。 0
答案 0 :(得分:4)
可以对你的案例进行一些简化,例如首先做好准备:
List<string> a = new List<string>() {"EN", "SU", "DT", "PR"};
List<string> b = new List<string>() {"Name", "Super", "Deran", "PRate"};
然后你可以这样做:
strSelectedType = ViewState[a[i-1]].ToString();
strSelectedCol = b[i-1];
然后,如果你有下拉列表,你也可以
var query = dtTest.AsEnumerable();
for (int i = 0; i < 4; ++i)
if (dropdown #i-1 index > 0) {
query = query.Where(r => r.Field<string>(strSelectedCol) == ViewState[strSelectedType].ToString());
var result = query.CopyToDataTable();
//Do something, your DataTable is here
}
您也可以使用List<KeyValuePair>
:
List<KeyValuePair<string,string>> lkvp = new List<KeyValuePair<string,string>>(){
new KeyValuePair("EN", "Name"),
new KeyValuePair("SU", "Super"),
new KeyValuePair("DT", "Deran"),
new KeyValuePair("PR", "PRate")
}
并像这样使用
strSelectedType = ViewState[lkvp[i-1].Key].ToString();
strSelectedCol = lkvp[i-1].Value;
答案 1 :(得分:3)
使用谓词构建器。
特别是当您不知道要过滤的确切选项时,它会有所帮助。在进入过滤点之前,您可以简单地构建谓词。
它可以改善您的应用程序执行情况,因为您不需要多次过滤您的收藏。
阅读以下链接: http://www.albahari.com/nutshell/predicatebuilder.aspx
答案 2 :(得分:2)
您可以逐步构建查询。只需有条件地添加新过滤器并将结果分配给原始查询变量:
var query = dtTest.AsEnumerable();
if (dropdown1.SelectedIndex > 0)
query = query.Where(r => r.Field<string>("Name") == ViewState["EN"].ToString());
if (dropdown2.SelectedIndex > 0)
query = query.Where(r => r.Field<string>("Super") == ViewState["SU"].ToString());
// etc
DataTable selectedTable = query.CopyToDataTable();
如果您可以更改ViewState键以便它们与下拉列表ID匹配(反之亦然),那么您可以轻松构建过滤器列表,然后将它们全部应用于循环中:
var columns = new Dictionary<string, string> {
["EN"] = "Name",
["SU"] = "Super",
["DT"] = "Deran",
["PR"] = "PRate"
};
var filters = from ddl in Controls.OfType<DropDownList>()
where ddl.SelectedIndex > 0 && columns.ContainsKey(ddl.ID)
select new {
Column = columns[ddl.ID],
Value = ViewState[ddl.ID].ToString()
};
var query = dtTest.AsEnumerable();
foreach(var fitler in filters)
query = query.Where(r => r.Field<string>(fitler.Column) == fitler.Value);
DataTable selectedTable = query.CopyToDataTable();
答案 3 :(得分:1)
Where
次来电话:
var rows = dtTest.AsEnumerable();
if (...)
rows = rows.Where(r => ...);
if (...)
rows = rows.Where(r => ...);
...
var result = rows.CopyToDataTable();
或者,如果您想存储条件供以后使用,您也可以这样做:
var conditions = new List<Func<DataRow, bool>>();
if (...)
conditions.Add(r => ...);
if (...)
conditions.Add(r => ...);
...
var query = dtTest.AsEnumerable();
foreach (var cond in conditions)
query = query.Where(cond);
var result = query.CopyToDataTable();