Question

我通过从非GUI线程到GUI线程的信号发出模型，以便创建QTableView并设置模型。不幸的是，应用程序崩溃了。当我在设置QTableView之前发布字典并在图表类中准备模型时，每次操作都有效。我究竟做错了什么？我使用的是Python 3.4和PyQt 5.4.1。

以下是代码段：

class CheckNE(QObject):

    #some code ...

    neTreeForEnvAlmsChanged = pyqtSignal(QStandardItemModel, QStandardItemModel)

    def check_bts_envalms(self, modelEnvBscAlm):  # i call it from other CheckNE member function

        #some code, i'm creating modelEnvBtsAlm here...

        print('Before emitting neTreeForEnvAlmsChanged')
        self.neTreeForEnvAlmsChanged.emit(modelEnvBtsAlm, modelEnvBscAlm)
        print('After emitting neTreeForEnvAlmsChanged')


class MainWindow(QMainWindow):

    #some code ...

    @pyqtSlot(QStandardItemModel, QStandardItemModel)
    def retrieveTreeForEnvAlm(self, modelBtsEnv, modelBscEnv):
        print('Receiving neTreeForEnvAlmsChanged')

        dialogTableWorker = TableDialog(modelBtsEnv, modelBscEnv)
        print('Before showing dialog')
        dialogTableWorker.show_table_dialog()
        print('After showing dialog')


class TableDialog(QDialog, Ui_Dialog_Table):
    def __init__(self, modelBts, modelBsc):
        print('Beginning init of TableDialog')
        super(TableDialog, self).__init__()
        self.setupUi(self)
        self.tableView.setModel(modelBts)  # tableView created in Qt Designer
        print('Ending init of TableDialog')

    def show_table_dialog(self):
        print('Showing TableDialog started')
        self.exec_()
        print('Showing TableDialog ended')


def main():

    app = QApplication(sys.argv)

    main_window = MainWindow()
    checkNeWorker = CheckNE()
    checkNeWorkerThread = QThread()

    main_window.show()
    main_window.raise_()

    checkNeWorker.moveToThread(checkNeWorkerThread)
    checkNeWorker.neTreeForEnvAlmsChanged.connect(main_window.retrieveTreeForEnvAlm)
    checkNeWorkerThread.start()

    app.exec_()

main()

结果：

Before emitting neTreeForEnvAlmsChanged
After emitting neTreeForEnvAlmsChanged

Process finished with exit code -1073741819 (0xC0000005)

但是当我使用断点进行调试时：

print('Before emitting neTreeForEnvAlmsChanged')

一切都像魅力一样：

Before emitting neTreeForEnvAlmsChanged
Receiving neTreeForEnvAlmsChanged
Beginning init of TableDialog
After emitting neTreeForEnvAlmsChanged
Ending init of TableDialog
Before showing dialog
Showing TableDialog started
Showing TableDialog ended
After showing dialog

Answer 1

在声明信号和插槽时需要引用类型，因为它们不是python类型，但它们是在C ++级别定义的。正如文档所说：定义信号的C ++签名的类型。每种类型可以是Python类型对象，也可以是C ++类型名称的字符串。

pyqtSignal('QStandardItemModel', 'QStandardItemModel')

和

@pyqtSlot('QStandardItemModel', 'QStandardItemModel')

应该解决你的问题。

发射QStandardItemModel时PyQt崩溃

1 个答案: