Question

我正在查询显示结果，我在mySQL中本地运行了完全相同的查询，我得到了所需的结果但是当通过以下代码执行时没有任何反应。

$JobID = '3214.GF.010.J45.TEA';
$ProjectID = '3214';    
$conn = new mysqli ($server,$username,$password,$dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} 
echo "Connected successfully <br>";
$stmt = $conn->prepare('Select jmpPartShortDescription, ujmpLevel, ujmpRoom, jmpClosed from Inf_Jobs');
//$stmt->bind_param('ss',$JobID,$ProjectID);
$stmt -> bind_result($Description,$Level,$Room,$Closed);
$stmt -> fetch();
$stmt -> close();
$conn -> close();

echo $Description .$Level .$Room .$Closed;

我无法理解为什么我没有得到任何结果我收到了Connected Successfully消息，但没有返回实际值。

Answer 1

你需要execute()准备好的声明才能让它做任何事情。

$stmt = $conn->prepare('Select jmpPartShortDescription, ujmpLevel, ujmpRoom, jmpClosed from Inf_Jobs');
//$stmt->bind_param('ss',$JobID,$ProjectID);

$stmt->execute(); // <- this is what does the work

$stmt -> bind_result($Description,$Level,$Room,$Closed);
$stmt -> fetch();

没有通过查询获得任何结果

1 个答案: