Question

    {
        Random r = new Random();
        int current = 0;
        int noa = 0;
        while (current != 6) {
            current =r.Next(1,7);
                noa += 1;
                Console.WriteLine(current + " has been rolled.");
        }

        if (noa >= 10)
        {
            Console.WriteLine("You were unlucky and it took you "+ noa + " times to roll a 6!");
        }
        if (noa <= 5)
        {
            Console.WriteLine("You were quite lucky and it took you " + noa + " times to roll a 6!");
        }
        else
        {
            Console.WriteLine("It took you " + noa + " times to roll a 6!");
        }

        Console.ReadKey();


    }
}

} 因此，当noa（尝试次数）高于10时会出现问题，它显示的是：

2已经滚动。
  5已经滚动。
  4已经滚动。
  5已经滚动。
  5已经滚动。
  1已经滚动。
  2已经滚动。
  1已经滚动。
  3已经滚动。
  4已经滚动。
  6已经滚动。
  你运气不好，你花了11次才打出一个6！   你花了11次滚动了6次！

我不想发生的事情是控制台写第二行“你花了11次才打了6个！”。为什么会这样？提前谢谢。

Answer 1

你必须把它elseif

if (noa >= 10)
{
    Console.WriteLine("You were unlucky and it took you "+ noa + " times to roll a 6!");
}
else if (noa <= 5)
{
    Console.WriteLine("You were quite lucky and it took you " + noa + " times to roll a 6!");
}
else
{
    Console.WriteLine("It took you " + noa + " times to roll a 6!");
}

修改同意@Kalmino，问题的原因是所有条件都在if... elseif... else的一个条件分支中一起处理。

Answer 2

因为这个

if (noa <= 5)
{
    Console.WriteLine("You were quite lucky and it took you " + noa + " times to roll a 6!");
}
else
{
    Console.WriteLine("It took you " + noa + " times to roll a 6!");
}

noa>5会怎样？

c＃否则没有按预期工作

2 个答案: