Question

我有一个非常大的JSON字符串（超过1mb）。它是这样开始的：

[[{ “时间戳”：1456815458， “total_jobs”：6398， “latest_height”：99045， “工作”：{“152.62.311.2:123":[8003,"/Main:5.1/",1655659260， 1,395047，“ec4.ap-southeast-3.amazonaws.com”，“Capetown”，“AU”， - 317.8815,57.5，“Australia / NSW”，“AS1511”，“Amazon.com，Inc。”] “183.215.34.58:9805”：56734， “/ JobPlace2：0.11.0 /”，1455767214,1,399047， “185.211.134.58”， “首尔”， “KR”，57.5983,126.9783，“亚洲/首尔”， “AS32665”， “HCLC”]，...

我希望能够回显IP地址以及IP地址附带的信息（每个IP地址后面有大约13条子信息）。

我该怎么做？我之前从未在解码过的JSON字符串中访问类/对象。

为了给出所需PHP输出的示例，对于第一个IP地址（152.62.311.2:123），它应该输出：

8003
  /Main:5.1/
  1655659260个
  1
  395047个
  ec4.ap-southeast-3.amazonaws.com
  开普敦
  AU
  -317.8815
  57.5
  澳大利亚/新南威尔士州
  AS1511
  Amazon.com，Inc

Answer 1

这可能不是最好的解决方案，但它是一个解决方案......

$decoded = json_decode($json);
$ipInfo= $decoded[0][0]->jobs->{'152.62.311.2:123'};
print_r($ipInfo);

jobs数组输出如下：

Array
(
    [0] => 8003
    [1] => /Main:5.1/
    [2] => 1655659260
    [3] => 1
    [4] => 395047
    [5] => ec4.ap-southeast-3.amazonaws.com
    [6] => Capetown
    [7] => AU
    [8] => -317.8815
    [9] => 57.5
    [10] => Australia/NSW
    [11] => AS1511
    [12] => Amazon.com, Inc.
)

您可以在此处查看示例：https://ideone.com/bzhhLI

如果您纯粹想要遍历并打印出所有可以执行此操作的信息，尽管这不是一个非常漂亮的解决方案：

$json = '[
    [{
        "timestamp": 1456815458,
        "total_jobs": 6398,
        "latest_height": 99045,
        "jobs": {
            "152.62.311.2:123": [8003, "/Main:5.1/", 1655659260, 1, 395047, "ec4.ap-southeast-3.amazonaws.com", "Capetown", "AU", -317.8815, 57.5, "Australia/NSW", "AS1511", "Amazon.com, Inc."],
            "183.215.34.58:9805": [56734, "/JobPlace2:0.11.0/", 1455767214, 1, 399047, "185.211.134.58", "Seoul", "KR", 57.5983, 126.9783, "Asia/Seoul", "AS32665", "HCLC"]
        }
    }]
]';




$decoded = json_decode($json);
$jobs = $decoded[0][0]->jobs->{'152.62.311.2:123'};

header('content-type: text/plain');
foreach ($decoded[0][0]->jobs as $ip => $ipData) {
    echo $ip . PHP_EOL;
    foreach ($ipData as $data) {
        echo $data . PHP_EOL;
    }
}

Answer 2

鸽子回答了这个问题。以下是简洁明了的答案：

$json_data = '[[{"timestamp": 1456815458,"total_jobs": 6398,"latest_height": 99045,"jobs": {"152.62.311.2:123": [8003,"/Main:5.1/", 1655659260, 1, 395047, "ec4.ap-southeast-3.amazonaws.com", "Capetown", "AU", -317.8815, 57.5, "Australia/NSW", "AS1511", "Amazon.com, Inc."],"183.215.34.58:9805": [56734, "/JobPlace2:0.11.0/", 1455767214, 1, 399047, "185.211.134.58", "Seoul", "KR", 57.5983, 126.9783, "Asia/Seoul", "AS32665", "HCLC"]}}]]';

$json_feed = json_decode($json_data);

foreach ($json_feed[0]->jobs as $ip => $ipData) {
    echo "<br><b>IP Address: ". $ip . "</b><br>";
    foreach ($ipData as $data) {
        echo "Data: ". $data . "<br>";
    }
}

如何访问此JSON字符串中的元素/对象？

2 个答案: