我正在尝试从MySQL工作台显示以下表格以在asp.net上显示
要在asp.net上显示表格,我使用网格视图,这里是以下代码:
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" OnRowCommand="GridView1_RowCommand" DataKeyNames ="child_id" OnSelectedIndexChanged="GridView1_SelectedIndexChanged" AllowPaging="True" OnPageIndexChanging="GridView1_PageIndexChanging">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="LinkButton1" runat="server" CommandName="SelectFullDetails">Select</asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
<asp:BoundField DataField="child_id" HeaderText="Id" />
<asp:BoundField DataField="child_firstname" HeaderText="FirstName" />
<asp:BoundField DataField="parent_surname" HeaderText="Surname" />
<asp:BoundField DataField="club_name" HeaderText="Club" />
</Columns>
</asp:GridView>
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
GridViewDataBind();
}
}
private void GridViewDataBind()
{
GridView1.DataSource = DetailsAccessLayer.GetAllChildBasicDetails();
GridView1.DataBind();
}
public class ChildBasic
{
public int child_id { get; set; }
public string child_firstname { get; set; }
public string parent_surname { get; set; }
public string club_name { get; set; }
}
public class DetailsAccessLayer
{
public static List<ChildBasic> GetAllChildBasicDetails()
{
List<ChildBasic> listChild = new List<ChildBasic>();
string CS = ConfigurationManager.ConnectionStrings["dbyouthworkConnectionString"].ConnectionString;
using (MySqlConnection con = new MySqlConnection(CS))
{
var InnerJoinClub = "SELECT child_details.child_id, child_details.child_firstname,child_details.parent_surname, enrolment_details.club_name FROM child_details INNER JOIN enrolment_details ON child_details.child_id = enrolment_details.child_id";
MySqlCommand cmd = new MySqlCommand(innerJoinClub, con);
con.Open();
MySqlDataReader rdr = cmd.ExecuteReader();
while (rdr.Read())
{
ChildBasic childbasic = new ChildBasic();
childbasic.child_id = Convert.ToInt32(rdr["child_id"]);
childbasic.child_firstname = rdr["child_firstname"].ToString();
childbasic.parent_surname = rdr["parent_surname"].ToString();
childbasic.club_name = rdr["club_name"].ToString();
listChild.Add(childbasic);
}
}
return listChild;
}
然而,每次我运行程序时,都会收到错误:类型&#39; System.Web.HttpException&#39;发生在System.Web.dll中但未在用户代码中处理
其他信息:名称为&#39; club_name&#39;的字段或媒体资源未在所选数据源中找到。
有人能告诉我代码中的错误以及如何纠正错误吗?
非常感谢
编辑:这是发生错误的地方
private void GridViewDataBind()
{
GridView1.DataSource = DetailsAccessLayer.GetAllChildBasicDetails();
GridView1.DataBind(); }
在 GridView1.DataBind()
答案 0 :(得分:0)
在SQL查询中,您需要为enrolment_details.club_name
提供别名,例如enrolment_details.club_name AS club_name
答案 1 :(得分:0)
尝试这样:
public DataTable ConvertToDatatable(List<ChildBasic> list)
{
DataTable dt = new DataTable();
dt.Columns.Add("child_id");
dt.Columns.Add("child_firstname");
dt.Columns.Add("parent_surname");
dt.Columns.Add("club_name");
foreach (var item in list)
{
var row = dt.NewRow();
row["child_id"] = item.child_id;
row["child_firstname"] = Convert.ToString(item.child_firstname);
row["parent_surname"] = Convert.ToString(item.parent_surname);
row["club_name"] = Convert.ToString(item.parent_surname);
dt.Rows.Add(row);
}
return dt;
}
private void GridViewDataBind()
{
GridView1.DataSource = ConvertToDatatable(DetailsAccessLayer.GetAllChildBasicDetails());
GridView1.DataBind();
}