Question

我有一个需要多选的列表视图（即每个列表项都有一个可以选中/取消选中的复选框）列表视图位于tabhost中，是第一个选项卡的内容。

我的设置是这样的：

我的标签设置为：

TabSpec tab = tabHost.newTabSpec("Services");

tabHost.addTab(tabHost.newTabSpec("tab_test1").setIndicator("Services").setContent(new Intent(this, ServiceList.class)));

单击选项卡时，将启动新活动ServiceList

ServiceList定义如下：

    public class ServiceList extends ListActivity{
        private EscarApplication application;
        ListView listView;
         @Override
           public void onCreate(Bundle savedInstanceState) {
             super.onCreate(savedInstanceState);
             setContentView(R.layout.service_list);
             ServiceList.this.application = (EscarApplication) this.getApplication();
             final ListView listView = getListView();
         }

         protected void onListItemClick(ListView l, View v, int position, long id) {
            String.valueOf(id);
            Long.toString(id);
            ((CheckedTextView) v).setChecked(true);
            super.onListItemClick(l, v, position, id);
        }

         @Override
         public void onStart() {
             super.onStart();
            //Generate and display the List of visits for this day by calling the AsyncTask
             GenerateServiceList services = new GenerateServiceList();
             int id = ServiceList.this.application.getVisitId();
             services.execute(id);
             listView  = getListView();
             listView.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);
         }

        //The AsyncTask to generate a list
         private class GenerateServiceList extends AsyncTask<Integer, String, Cursor> {
              // can use UI thread here
              protected void onPreExecute() {
              }
              // automatically done on worker thread (separate from UI thread)
              protected Cursor doInBackground(Integer...params) {
                  int client_id = params[0];
                  ServiceList.this.application.getServicesHelper().open();
                  Cursor cur = ServiceList.this.application.getServicesHelper().getPotentialVisitServices(client_id);
                  return cur; 

              }
              // can use UI thread here
              protected void onPostExecute(Cursor cur){  
                  startManagingCursor(cur);
                  // the desired columns to be bound
                  String[] columns = new String[] {ServicesAdapter.KEY_SERVICE};
                  // the XML defined views which the data will be bound to
                  int[] to = new int[] {R.id.display_service};
                  SimpleCursorAdapter mAdapter = new SimpleCursorAdapter(ServiceList.this, R.layout.service_list_element, cur, columns, to);
                  // set this adapter as your ListActivity's adapter
                  ServiceList.this.setListAdapter(mAdapter);
ServiceList.this.application.getServicesHelper().close();       

              }
         }
    }

所以，一切正常，直到我点击我的列表项来更改复选框状态。

设置处理点击事件的代码部分导致我出现问题：

 protected void onListItemClick(ListView l, View v, int position, long id) {
                String.valueOf(id);
                Long.toString(id);
                ((CheckedTextView) v).setChecked(true);
                super.onListItemClick(l, v, position, id);
            }

我的理解是传递给onListItemClick方法的View v重新呈现了我的list元素，所以我试图将v作为CheckedTextView进行转换并将teh checked值设置为true，但这只会导致我的应用程序崩溃。我在这里遗漏了一些简单的东西，还是有更简单的方法来做到这一点？

由于

凯文

Answer 1

你调试过它来检查'v'是否为空？如果是这样，您需要使用layoutInflator来检索视图。

if(v == null)
{
    LayoutInflater vi = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    v = vi.inflate(R.layout.service_list, null);
}

Android CheckedTextView - 单击更改已检查状态

1 个答案: