Question

我使用以下代码，我得到同一个人的多个姓名和电话号码。如何才能获得我拨打过的所有用户的单个姓名和手机号码。

代码：

     if (android.os.Build.VERSION.SDK_INT >= 21) {
                mCursor = managedQuery(ContactsContract.Data.CONTENT_URI, null, ContactsContract.Contacts.Data.MIMETYPE + "='" + ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE + "'", null, ContactsContract.Data.CONTACT_LAST_UPDATED_TIMESTAMP + " DESC");
            }else{
                mCursor = managedQuery(ContactsContract.Data.CONTENT_URI, null, ContactsContract.Contacts.Data.MIMETYPE + "='" + ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE + "'", null, ContactsContract.Data.LAST_TIME_CONTACTED + " DESC");
            }
            int number = mCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
            int name = mCursor.getColumnIndex(ContactsContract.Data.DISPLAY_NAME);

            while (mCursor.moveToNext()) {
                String phName = mCursor.getString(name);
                String phNumber = mCursor.getString(number);
    }                       

}

更新代码：

 ContentResolver cr = getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);

        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
                if (Integer.parseInt(cur.getString(
                        cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {

                    Cursor pCur =  cr.query(ContactsContract.Data.CONTENT_URI,
                            new String[]{ContactsContract.Data._ID, ContactsContract.CommonDataKinds.Phone.NUMBER, ContactsContract.CommonDataKinds.Phone.TYPE, ContactsContract.CommonDataKinds.Phone.LABEL},
                            ContactsContract.Data.CONTACT_ID + "=?" + " AND "
                                    + ContactsContract.Data.MIMETYPE + "= + Phone.CONTENT_ITEM_TYPE + ",
                            new String[]{String.valueOf(id)}, null);


                    while (pCur.moveToNext()) {
                        String phoneNo = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                        Log.w("num", "Name: " + name + ", Phone No: " + phoneNo);
                    }
                    pCur.close();
                }
            }
        }

Answer 1

您应该使用以下特定字段来代替manageQuery，并将其保留在SELECT查询中。以下只是示例，您可以根据您的要求参考和使用：

Cursor c = getContentResolver().query(Data.CONTENT_URI,
                                      new String[] {Data._ID, Phone.NUMBER, Phone.TYPE, Phone.LABEL},
                                      Data.CONTACT_ID + "=?" + " AND "
                                              + Data.MIMETYPE + "= + Phone.CONTENT_ITEM_TYPE + ",
                                      new String[] {String.valueOf(contactId)}, null);

从电话簿获取最后一个手机号码唯一用户（仅显示最后拨打的号码）

1 个答案: