Question

我需要在两个日期（例如1年）之间按名称显示房屋。我尝试了以下请求，但它不起作用。

SELECT * 
FROM DATA1 
WHERE facility='house' 
    AND datee BETWEEN '2014-02-01' AND '2015-02-31'
GROUP BY name 
ORDER BY datee ASC;

Answer 1

这是解决方案！

SELECT * 
FROM DATA1
WHERE facility= 'house'
AND datee BETWEEN '2014-02-01' AND '2015-02-28'
ORDER BY facility,datee ASC

Answer 2

嗨，你可以使用这些

SELECT * FROM DATA WHERE facility= 'house' 
AND( From_date >= '2013-01-03' AND  To_date <= '2013-01-09')
GROUP BY name 
ORDER BY datee ASC;

Answer 3

这个解决方案可能对您有所帮助。

SELECT * 
FROM DATA1 
WHERE facility= 'house' 
    AND (cast(datee as date)) BETWEEN (cast('2014-02-01' as date) AND cast('2015-02-28' as date)) 
ORDER BY name, datee ASC;

Answer 4

试试这个，它可能对你有帮助。

SELECT * FROM DATA1 
WHERE facility= 'house' 
AND (dateE BETWEEN YEAR(2014-02-01) AND YEAR(2015-02-31) )
GROUP BY name ORDER BY datee ASC;

查询两个日期和另一个数据

4 个答案: