Question

我有一个看起来像这样的数组。这是一个二维数组。

$MainArray = Array
(
    [0] => Array
        (
            [Job_Name] => WXYZ
            [Quantity] => 1000
            [Machine_Name] => Machine1
            [Start_Date] => 2014-07-30 00:00:00
            [Completion_Date] => 2014-08-02 00:00:00
            [Labor] => 4
        )
    [1] => Array
        (
            [Job_Name] => ABCD
            [Quantity] => 1500
            [Machine_Name] => Machine2
            [Start_Date] => 2014-08-08 00:00:00
            [Completion_Date] => 2014-08-14 00:00:00
            [Labor] => 2
        )
    [2] => Array
        (
            [Job_Name] => BCDA
            [Quantity] => 1200
            [Machine_Name] => Machine1
            [Start_Date] => 2014-08-02 00:00:00
            [Completion_Date] => 2014-08-07 00:00:00
            [Labor] => 1
        )
 )

我想使用这些信息来创建一个看起来像这样的新三维数组。

$ConvertedArray = Array
(
    [Machine1] => Array
        (
            [0] => Array
               (
                  [Job_Name] => WXYZ
                  [Quantity] => 1000
                  [Start_Date] => 2014-07-30 00:00:00
                  [Completion_Date] => 2014-08-02 00:00:00
                  [Labor] => 4
               )
            [1] => Array
               (
                  [Job_Name] => BCDA
                  [Quantity] => 1200
                  [Start_Date] => 2014-08-02 00:00:00
                  [Completion_Date] => 2014-08-07 00:00:00
                  [Labor] => 1
               )
         )
      [Machine2] => Array
        (
            [0] => Array
               (
                  [Job_Name] => ABCD
                  [Quantity] => 1500
                  [Machine_Name] => Machine2
                  [Start_Date] => 2014-08-08 00:00:00
                  [Completion_Date] => 2014-08-14 00:00:00
                  [Labor] => 2
               )
         )   
)

请提供任何帮助，我们将不胜感激。我遇到了困难，需要弄清楚如何使用这个原始数组创建新数组。所以基本上我将每台机器的所有作业分组在一起，这些作业的关键取决于它们在原始阵列中的位置。因此，如果原始数组具有键2的作业，并且该机器上没有其他作业具有更高的键，那么它将成为该作业的键0并创建具有该机器名的新键。

我真的很感谢你的帮助。

Answer 1

使用以下代码： -

$result = [];
foreach($MainArray as $record){
 $result[$record['Machine_Name']][] = $record;
}

echo '<pre>'; print_r($result);

输出： -

Array
(
    [Machine1] => Array
        (
            [0] => Array
               (
                  [Job_Name] => WXYZ
                  [Quantity] => 1000
                  [Start_Date] => 2014-07-30 00:00:00
                  [Completion_Date] => 2014-08-02 00:00:00
                  [Labor] => 4
               )
            [1] => Array
               (
                  [Job_Name] => BCDA
                  [Quantity] => 1200
                  [Start_Date] => 2014-08-02 00:00:00
                  [Completion_Date] => 2014-08-07 00:00:00
                  [Labor] => 1
               )
         )
      [Machine2] => Array
        (
            [0] => Array
               (
                  [Job_Name] => ABCD
                  [Quantity] => 1500
                  [Machine_Name] => Machine2
                  [Start_Date] => 2014-08-08 00:00:00
                  [Completion_Date] => 2014-08-14 00:00:00
                  [Labor] => 2
               )
         )   
)

Answer 2

foreach ($MainArray as $value) {
    $name = $value['Machine_Name'];
    unset($value['Machine_Name']);
    $ConvertedArray[$name][] = $value;
}

在php中从另一个数组创建一个数组

2 个答案: