Question

如果应用在前台接收到通知，我会尝试使用Toast显示横幅。

简单的案例没有任何问题。

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {
    UIView *parentView = [UIApplication sharedApplication].keyWindow.rootViewController.view;
    [parentView makeToast:@"toast"];
}

但是，当我尝试显示自己的自定义视图时，EXC_BAD_ACCESS方法出现错误showToast错误：

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {
    UIView *bannerView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, self.topController.view.frame.size.width, 80)];
    UIView *parentView = [UIApplication sharedApplication].keyWindow.rootViewController.view;
    bannerView.backgroundColor = [UIColor redColor];
    [parentView showToast: bannerView duration:3.0 position:CSToastPositionTop completion:nil];
}

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo方法是编程此类行为的危险场所吗？强烈引用parentView似乎不能正常工作，如何确定哪个对象被过度释放？

Answer 1

您可以直接在appdelegate窗口上显示吐司，而不是获取父视图，该视图位于所有视图的顶层。

-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{


    if (application.applicationState == UIApplicationStateActive)
    {
       [self.window makeToast:@"This is a piece of toast."];
    }
}

显示远程通知时应用程序崩溃

1 个答案: