获取sql结果作为嵌套的json对象

Question

通过while循环使用sql查询和group_concat，我实现了以下结果：

$rows[] = array('name' =>$row['customer'] , 'atw' =>$row['atw_number'] ,
     'dr' =>array(array('drnumber'=>(($row['dr_number'])),)),);

{       “名称”：“MULTIBUILD CORP”，       “atw”：“7146”，       “博士”：[         {           “drnumber”：“1608,1610,1611”         }       ]     }，

相反，我可以有类似的东西：

{       “名称”：“MULTIBUILD CORP”，       “atw”：“7146”，       “博士”：[         {           “drnumber”：“1608”         }，         {           “drnumber”：“1610”         }，         {         “drnumber”：“1611”         }       ]     }，

Answer 1

在while循环中，将当前$rows[] = ...替换为：

$numbers = [];
foreach (explode(',', $row['dr_number']) as $number)
    $numbers[] = ['dr_number' => $number];

$rows[] = array(
    'name' => $row['customer'],
    'atw' => $row['atw_number'],
    'dr' => $numbers
);