我喜欢写一个csv导入/更新到我的Mysql数据库,但它不起作用。我没有收到错误消息。
请允许任何人帮助我找到错误或我的脚本有什么问题。
// set local variables
$connect = mysql_connect("localhost","root","") or die('Could not connect: ' . mysql_error());
$handle = fopen("imptest.csv", "r");
// connect to mysql and select database or exit
mysql_select_db("shoptest1", $connect);
while($data = fgetcsv($handle, 30000, ';')) //Jede Zeile durchgehen
{
$Product_ID=$data[0];
$field=$data[1];
$query = 'SELECT Product_ID FROM testprod';
if (!$result = mysql_query($query)) {
continue;
} if ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
// entry exists update
$query = "UPDATE ps_product_lang SET custom_field ='$field' WHERE id_product = '$Product_ID'";
mysql_query($query);
if (mysql_affected_rows() <= 0) {
echo "kein update";
// no rows where affected by update query
}
} else {
echo "kein eintrag";
// entry doesn't exist continue or insert...
}
mysql_free_result($result);
}
fclose($handle);
mysql_close($connect);
?>
答案 0 :(得分:0)
您正在执行的查询:
SELECT Product_ID FROM testprod
UPDATE nl_product_lang SET custom_field = ? WHERE Product_ID = ?
适用于检测产品是否存在,然后是UPDATE或INSERT。对于仅UPDATE,SELECT无关紧要,因为没有条目WHERE Product_ID NOT IN (SELECT Product_ID FROM testprod)
- 如果您有外键。
以下是使用PDO执行此操作的示例。
list( $SQLDSN, $SQLUSER, $SQLPASS ) = [ 'mysql:dbname=shoptest1', 'root', '' ];
$db = new PDO( $SQLDSN, $SQLUSER, $SQLPASS, [
PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8',
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
] );
$ids = $db->query( "SELECT Product_ID from testprod" )->fetchAll( \PDO::FETCH_COLUMN, 0 );
while ( list( $Product_ID, $field ) = fgetcsv(...) )
if ( in_array( $Product_ID, $ids ) )
query( $db, "UPDATE ps_product_lang SET custom_field = ? WHERE Product_ID = ?",
[ $field, $Product_ID ]
);
else
trigger_warning( "unknown product $Product_ID" );
function query( $db, $sql, $args = null ) {
$sth = $db->prepare( $sql );
$sth->execute( $sql );
return $sth;
}