Symfony2 2.7
我环顾四周，但我找不到一种简洁，标准的定义方式：
（*）一个表单（formType）以及让用户动态创建任意数量的对象所需的控制器。
问题是：有没有标准的方法（*）？
注意：This似乎没有帮助，因为它只创建一个唯一的Task对象，即使它允许用户创建（动态）多个Tag对象。
部分解决方案 以下工作正常：用户可以添加任意数量的对象。
我需要检查一下是否可以以某种方式清理代码。 如果你有办法改进它，请发表评论。
最终，我希望有一个Job 1：M任务1：M标签的情况，用一个表格立即创建多个作业，每个作业有很多任务，每个任务有很多标签。我需要检查我是否可以为相关的1：M实体嵌入表单。请继续关注！
控制器
/**
* Creates a new Job entity.
*
* @Route("/", name="Myname_Job_create")
* @Method("POST")
* @Template("MynameBlogBundle:Job:new.html.twig")
*/
public function createAction(Request $request)
{
////var_dump($request); die('here'); // this helped a lot to understand
$postData = $request->request->get('form');
$entity = array();
foreach($postData['jobs'] as $key => $obj){$entity[$key]= new Job();}
$form = $this->createCreateForm($entity);
$form->handleRequest($request);
if ($form->isValid()) {
try {
$em = $this->getDoctrine()->getEntityManager();
foreach($entity as $ent){ $em->persist($ent); }
$em->flush();
} catch (\Doctrine\DBAL\DBALException $e) {
die($e->getMessage());
}
return $this->redirect($this->generateUrl('Myname_Job'));
}
return array(
'info' => $postData,
'entity' => $entity,
'form' => $form->createView(),
);
}
/**
* Creates a form to create a Job entity.
*
* @param Job $entity The entity
*
* @return \Symfony\Component\Form\Form The form
*/
private function createCreateForm(Array $jobs)
{
$form = $this->createFormBuilder(array('jobs'=>$jobs))
->setAction($this->generateUrl('Myname_Job_create'))
->add('jobs','collection',array(
'required' => true,
'allow_add' => true,
'allow_delete' => true,
'type' => new JobType(),
))
->add('submit', 'submit',array('label' => 'Create'))
->getForm()
;
return $form;
}
/**
* Displays a form to create a new Job entity.
*
* @Route("/new", name="Myname_Job_new")
* @Method("GET")
* @Template()
*/
public function newAction()
{
$jobs = array(0 => new Job());
$form = $this->createCreateForm($jobs);
return array(
'entity' => $jobs,
'form' => $form->createView(),
);
}
JobType
class JobType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('title', 'text', array(
'label' => 'Write Title ',
'required' => true
))
->add('description','text',array(
'label' => 'Write Descr. ',
))
;
}
....
}
新的.twig模板
{% extends '::base.html.twig' %}
{% block javascripts %}
{{ parent() }}
<script src="{{ asset('bundles/mynameblog/js/JQuery/jquery-2.1.0.js') }}" type="text/javascript">
</script>
<script>
var $collectionHolder;
// setup an "add aJobs" link
var $addJobLink = $('<a href="#" class="add_Job_link">Add Jobs</a>');
var $newLinkLi = $('<li></li>').append($addJobLink);
function addJobForm($collectionHolder, $newLinkLi) {
// Get the data-prototype explained earlier
var prototype = $collectionHolder.data('prototype');
// get the new index
var index = $collectionHolder.data('index');
// Replace '__name__' in the prototype's HTML to
// instead be a number based on how many items we have
var newForm = prototype.replace(/__name__/g, index);
// increase the index with one for the next item
$collectionHolder.data('index', index + 1);
// Display the form in the page in an li, before the "Add a Jobs" link li
var $newFormLi = $('<li></li>').append(newForm);
$newLinkLi.before($newFormLi);
}
jQuery(document).ready(function() {
// Get the ul that holds the collection of Jobs
$collectionHolder = $('ul.jobs');
// add the "add Jobs" anchor and li to the Jobs ul
$collectionHolder.append($newLinkLi);
// count the current form inputs we have (e.g. 2), use that as the new
// index when inserting a new item (e.g. 2)
$collectionHolder.data('index', $collectionHolder.find(':input').length);
$addJobLink.on('click', function(e) {
// prevent the link from creating a "#" on the URL
e.preventDefault();
// add a newJobs form (see next code block)
addJobForm($collectionHolder, $newLinkLi);
});
});
</script>
{% endblock %}
{% block main -%}
<h1>Job creation</h1>
{{ form_start(form) }}
<ul class="jobs" data-prototype="{{ form_widget(form.jobs.vars.prototype)|e }}">
{# render the job-s only two fields: title description #}
{% for f in form.jobs %}
<li> {{ form_row(f) }} </li>
{% endfor %}
</ul>
{{ form_end(form) }}
{% endblock %}
答案 0 :(得分：0)
建议：使用一个客户端操作添加多个对象的最佳方式：
所以很简单...... 无需复杂的表格来管理接收已发布请求的控制器中的多个实体。
但是，要做你想做的事情：
这是一种做你想做的事的方法。 我只强调了如何在服务器端调整表单。 我无法测试你的JS，在这里我假设你在表单中添加[title_1，description_1，title_2，description_2，...]等字段。
你也应该适应：
我建议您使用“objects_count”选项调整表单： （请注意，您应该处理没有类的表单（不应在configureOptions中定义data_class））
class JobType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
// This is called once you posted your form to recreate the JS generated
// fiels on the server side. Otherwise, these fiels are ignorated
if($options['objects_count']>0){
for($i=0;$i<$options['objects_count'];$i++){
$builder
->add('title_'.$i, TextType::class)
->add('description_'.$i, TextType::class)
;
}
}
// This is called to render the first form
else{
$builder
->add('title', TextType::class)
->add('description', TextType::class)
;
}
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(array('objects_count'=>0));
}
}
然后，要处理此表单，您必须获取已过帐字段的计数：
你的控制器：
/**
* Creates a new Job entity.
*
* @Route("/", name="Myname_Job_create")
* @Method("POST")
* @Template("MynameBlogBundle:Job:new.html.twig")
*/
public function createAction(Request $request)
{
$i = 1;
$defaults = array();
while($request->request->has('title_'.$i)){
$defaults += array('title_'.$i=>"",'description_'.$i=>"");
$i++;
}
$objects_count = $i-1;
if($objects_count === 0){
$defaults = array('title'=>"",'description'=>"");
}
$form = $this->$defaults(JobType::class,$defaults,array('objects_count'=>$objects_count));
$form->handleRequest($request);
// ...
}