所以我有一个像这样的结构表:
classdef MobileBaseStation
properties(GetAccess=private, SetAccess=private)
DataChannel = struct('TxScheme','SpatialMux','NLayers',4);
end
...
properties(Dependent=true)
TxScheme;
NLayers;
end
methods
function v = get.TxScheme(this), v = this.DataChannel.TxScheme; end
function v = get.NLayers(this), v = this.DataChannel.NLayers; end
function this = set.TxScheme(this,v)
assert(ismember(v,this.supportedTxSchemes),'Invalid TxScheme - %s.',v);
this.DataChannel.TxScheme = v;
end
...
end
end
我想要做的是在用户点击编辑时从第一列获取Id的值。如果你想嘲笑我失败的尝试,那就是:
<table>
<thead>
<tr>
<th>Id</th>
<th>Name</th>
<th>Company</th>
<th>Position</th>
<th>Start Date</th>
<th>Role</th>
<th></th>
</tr>
</thead>
<tbody>
<tr>
<td><?php info displayed with php ?></td>
<td><?php info displayed with php ?></td>
<td><?php info displayed with php ?></td>
<td><?php info displayed with php ?></td>
<td><?php info displayed with php ?></td>
<td><?php info displayed with php ?></td>
<td><a href="#" class="usr-edit">Edit</a></td>
</tr>
</tbody>
</table>
答案 0 :(得分:4)
$('.usr-edit').click(function() {
var a = $(this).closest('tr').find('td:nth-child(1)').text();
console.log(a);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<table>
<thead>
<tr>
<th>Id</th>
<th>Name</th>
<th>Company</th>
<th>Position</th>
<th>Start Date</th>
<th>Role</th>
<th></th>
</tr>
</thead>
<tbody>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
<td><a href="#" class="usr-edit">Edit</a>
</td>
</tr>
</tbody>
</table>
试试这个
答案 1 :(得分:0)
你可以在表元素中使用dom引用来获取你想要的单元格
var td = this;
var tr = this.parentNode;
var firstTd = tr.cells[0];
答案 2 :(得分:0)
简单!
$('.usr-edit').click(function() {
var a = $(this).parent().find('td:first-child').text();
console.log(a);
});
编辑:要找到tr
父母,您就可以这样做。
$('.usr-edit').click(function() {
var a = $(this).parents('tr').find('td:first-child').text();
console.log(a);
});
肮脏的方式
$('.usr-edit').click(function() {
var a = $(this).parent().parent().find('td:first-child').text();
console.log(a);
});
答案 3 :(得分:0)
您可以在<tr>
<tr class="yourClass">
上添加课程,并使用:
$('.yourClass').find('td:first-child').text();