Question

每当我打开我的框架时，windowOpened应该打印“打开”，但它不打印。所有其他抽象方法都正常工作。我正在使用Java 7.对此行为的任何想法。

public class windowlistenerdemo extends Frame implements WindowListener 
{
    public windowlistenerdemo()
    {
        setSize(400,400);
        setVisible(true);
        this.addWindowListener(this);
    }

    @Override
    public void windowOpened(WindowEvent e) {
        System.out.println("open");
    }

    @Override
    public void windowClosing(WindowEvent e) {
        System.out.println("closing");
        this.dispose();
     }

    @Override
    public void windowClosed(WindowEvent e) {
        System.out.println("closed");
    }

    public static void main(String[] args) {
        windowlistenerdemo ob = new windowlistenerdemo();
    }
}

Answer 1

listener

您要在添加windowOpened之前将窗口设置为可见。 public partial class Form1 : Form { public Form1() { InitializeComponent(); } Dictionary<string, UserControl1> myControls = new Dictionary<string, UserControl1>(); private void Form1_Load(object sender, EventArgs e) { // you could create the controls manually (i.e. not in designer) // add them to a dictionary // and also add them to the form, or whatever container you want for (int i = 0; i < 40; i++) { var newControl = new UserControl1 { Top = (i%10)*30, Left = (i/10)*200, }; myControls.Add("iButton" + ("ABCD"[(i / 10)]) + (i % 10), newControl); this.Controls.Add(newControl); } // now you can reference any of these controls like this: var letter = "B"; var num = "8"; var buttonItem = myControls["iButton" + letter + num].iButtonItem; } }事件已经解雇。尝试交换这些行。

windowOpened在java中无法正常工作

1 个答案: