Question

有人可以帮我解释一下为什么我会在下面的代码中出现这个错误，请：

<html>
    <head>
    </head>
    <body>
        <?php
            if (!(isset($_COOKIE["loggedin"]))){
                ?>
                <form action="<?php echo $_SERVER['PHP_SELF']?>" method="POST" name="name_form">
                    Username <input type="text" name="username">
                    <br/>
                    Password <input type="text" name="password">
                    <br/>
                    Remember Me <input type ="checkbox" name="remember_me" value="1">
                    <br/>
                    <input type="submit" name="submit" value="Log in">
                </form>
            }
    </body>
</html>

<?php

        if(preg_match("/<|>/", $_POST["username"])){    
            echo "do not log in";
        } 
        else if(preg_match("/<|>/", $_POST["password"])){   
            echo "do not log in";
        }
        else{
            //Open/create passwords.txt
            $passwordsFile = fopen("passwords.txt", "a");
            //write users username and password to passwords.txt
            $text_written = fwrite($passwordsFile, $_POST["username"] . "," . $_POST["password"] . "\r\n");
            fclose($passwordsFile);
            setcookie("loggedin", $_POST['username']);
            setcookie("loggedintime", time());
        }
    ?>

提前感谢您的帮助！我在这里看过类似的帖子，但无论如何我都无法解决这个问题......

Answer 1

在结束PHP标记?>之前，您似乎有一个额外的大括号，并且您忘记包装IF语句的前一个大括号}：{{1}使用PHP结束和结束标记，正确的代码：

if (!(isset($_COOKIE["loggedin"]))){

Answer 2

在php块中完成if括号..

<html>
<head>
</head>
<body>
    <?php
        if (!(isset($_COOKIE["loggedin"]))){
            ?>
            <form action="<?php echo $_SERVER['PHP_SELF']?>" method="POST" name="name_form">
                Username <input type="text" name="username">
                <br/>
                Password <input type="text" name="password">
                <br/>
                Remember Me <input type ="checkbox" name="remember_me" value="1">
                <br/>
                <input type="submit" name="submit" value="Log in">
            </form>
       <?php  } ?>
</body>

Answer 3

我在您的代码中进行了一些更改，第一个if条件的右括号在php标记（<html> <body> <p> Lorem ipsum dolor sit amet enim. <span class="tooltip" data-text="Tooltip1"> Etiam ullamcorper.</span>Suspendisse a pellentesque dui, non felis. <span class="tooltip" data-text="Tooltip 2">Maecenas malesuada elit lectus</span> felis, malesuada ultricies. Curabitur et ligula.<span class="tooltip" data-text="Tooltip 3">Ut molestie a, ultricies porta urna.</span> Vestibulum </p> </body> </html> <script> document.addEventListener("DOMContentLoaded", function() { var tooltips = document.querySelectorAll(".tooltip"); var tooltipsValue = []; console.log(tooltips); for (var i = 0; i < tooltips.length; i++) { var dataTags = tooltips[i].dataset.text; tooltipsValue.push(dataTags); //console.log(i); //console.log(tooltipsValue); //console.log(dataTags); //tooltips[i].dataset.text; //var dataTag = tooltips[i].dataset.text; //console.log(tooltips[i].dataset.text); tooltips[i].addEventListener('mouseover', function() { //console.log("text while mouseover"); //console.log(tooltipsValue[i]); }); tooltips[i].addEventListener('mouseout', function() { //console.log("text after mouseout"); }); } }); </script>）中没有。尝试给password.txt文件读写权限

<?php ... ?>

Answer 4

尝试

 if (!isset($_COOKIE["loggedin"])){

而不是

 if (!(isset($_COOKIE["loggedin"]))){

语法错误，意外的文件结束 - 看不清楚原因

4 个答案: