Question

这可能很简单，但我试图解决这个问题时遇到了一点灾难。我在PHP中有一个关联数组，如下所示：

$people= array (["Name" => "Sandra", "Age" => "21"], ["Name" => "Frank", "Age" => "34"], ["Name" => "Marc", "Age" => "56"]);

现在，如果我想知道数组中两个已知元素的年龄，那就说，桑德拉和弗兰克。我试着这样做：

foreach($people as $i){
    foreach($i as $info => $v){
        if($info == "Name"){
            if($v == "Sandra" || $v == "Frank"){
                    echo $v." has ". $v;            
            }
        }
    }
}

结果是：桑德拉有桑德拉。但这当然不是应该印刷的东西。有人能让我理解这个简单的问题吗？

Answer 1

为什么2个foreach循环，你可以通过一个foreach循环来实现它：

$people = array(["Name" => "Sandra", "Age" => "21"], ["Name" => "Frank", "Age" => "34"], ["Name" => "Marc", "Age" => "56"]);

foreach ($people as $v) {


    if ($v["Name"] == "Sandra" || $v["Name"] == "Frank") {
        echo $v["Name"] . " has " . $v["Age"];
        echo "<br />";
    }

}

<强>输出：

Sandra has 21
Frank has 34

Answer 2

首先，您正在使用两种在PHP中使用数组的约定。它有时变得不清楚，所以只使用一个约定，例如：

$people= [["Name" => "Sandra", "Age" => "21"], ["Name" => "Frank", "Age" => "34"], ["Name" => "Marc", "Age" => "56"]]

或

$people= array(array("Name" => "Sandra", "Age" => "21"), array("Name" => "Frank", "Age" => "34"), array("Name" => "Marc", "Age" => "56"))

您的问题有解决方案：

foreach($people as $person)
    if($person['Name'] == "Sandra" || $person['Name'] == "Frank")
        echo $person['Name'] . ' has ' . $person['Age'];

Answer 3

试试这个：

$flag = false;
foreach($people as $i){
    foreach($i as $info => $v){
        if($info == "Name"){
            if($v == "Sandra" || $v == "Frank"){
                echo $v." has "; 
                $flag = true;
            }
            else
                $flag = false;
        }
        if($info == "Age" && $flag){

            echo $v;          
        }
    }
}

关联数组PHP，从已知数据开始获取数据

3 个答案: