我的项目中有一个日历实体,负责管理全年营业日的开放和关闭时间。 以下是特定月份的记录
id | today_date | year | month_of_year | day_of_month | is_business_day
-------+---------------------+------+---------------+-------------+---------------+
10103 | 2016-02-01 00:00:00 | 2016 | 2 | 1 | t
10104 | 2016-02-02 00:00:00 | 2016 | 2 | 2 | t
10105 | 2016-02-03 00:00:00 | 2016 | 2 | 3 | t
10106 | 2016-02-04 00:00:00 | 2016 | 2 | 4 | t
10107 | 2016-02-05 00:00:00 | 2016 | 2 | 5 | t
10108 | 2016-02-06 00:00:00 | 2016 | 2 | 6 | f
10109 | 2016-02-07 00:00:00 | 2016 | 2 | 7 | f
10110 | 2016-02-08 00:00:00 | 2016 | 2 | 8 | t
10111 | 2016-02-09 00:00:00 | 2016 | 2 | 9 | t
10112 | 2016-02-10 00:00:00 | 2016 | 2 | 10 | t
10113 | 2016-02-11 00:00:00 | 2016 | 2 | 11 | t
10114 | 2016-02-12 00:00:00 | 2016 | 2 | 12 | t
10115 | 2016-02-13 00:00:00 | 2016 | 2 | 13 | f
10116 | 2016-02-14 00:00:00 | 2016 | 2 | 14 | f
10117 | 2016-02-15 00:00:00 | 2016 | 2 | 15 | t
10118 | 2016-02-16 00:00:00 | 2016 | 2 | 16 | t
10119 | 2016-02-17 00:00:00 | 2016 | 2 | 17 | t
10120 | 2016-02-18 00:00:00 | 2016 | 2 | 18 | t
我希望获得过去7个工作日期的today_date。支持today_date为2016-02-18
,过去7个工作日期的日期为2016-02-09
。
答案 0 :(得分:1)
您可以像这样使用row_number():
SELECT * FROM
(SELECT t.*,row_number() OVER(order by today_date desc) as rnk
FROM Calender t
WHERE today_date <= current_date
AND is_business_day = 't')
WHERE rnk = 7
这将为您提供从今天起第7个工作日的行
答案 1 :(得分:0)
我看到您使用Doctrine,ORM和Datetime标记了您的问题。你是在使用QueryBuilder解决方案吗?也许这更接近你想要的东西:
$qb->select('c.today_date')
->from(Calendar::class, 'c')
->where("c.today_date <= :today")
->andWhere("c.is_business_day = 't'")
->setMaxResults(7)
->orderBy("c.today_date", "DESC")
->setParameter('today', new \DateTime('now'), \Doctrine\DBAL\Types\Type::DATETIME));