我有两张桌子
rental_detail
- > [id
,Building
,Floor
,Flate_no
,Name
,doj
] rental_detail
存储此人的信息
这是rental_detail
|id|name|building|Floor|Flate_no|doj
|1 |aana| C | 1st |c-101 |06-12-2015
并在
Monthly_rent
- > [id
,Building
,Floor
,Flate_no
,date
]存储每月每月租金的详细信息这是month_rent
|id|building|Floor|Flate_no|date |rent|
|1 | C | 1st |c-101 |02-01-2016|2000
|2 | C | 1st |c-101 |03-02-2016|2000
|1 | C | 1st |c-101 |06-12-2015|2000
我需要Monthly_rent
的最长日期以及rental_detail
的人的所有信息,其中建筑物为c,楼层为1,flate为c-101
我尝试了此查询:
select *,max(mr.date) as m
from monthly_rent mr
Inner join rental_details rd
on rd.building='C' and rd.floor = '1st' And rd.flate_no='C-101
我需要这个
|1|aana|C|1st|c-101|03-02-2016|
aana在03-02-2016支付最后租金
答案 0 :(得分:2)
试试这个:
SELECT rd .*,mr.date AS mr_date
FROM rental_details rd
LEFT JOIN monthly_rent mr
ON rd.date = (SELECT MAX(date) FROM monthly_rent WHERE building='C' )
WHERE rd.building='C' AND rd.floor = '1st' AND rd.flate_no='C-101'
答案 1 :(得分:0)
试试这个:
select *, max(mr.date) as m
from monthly_rent mr, rental_details rd
where mr.id = rd.id
and rd.building='C'
and rd.floor = '1st'
and rd.flate_no='C-101'
这应该有效....
答案 2 :(得分:0)
尝试这样,它应该有帮助..
select rd.*,max(mr.date) as m
from monthly_rent as mr
LEFT join rental_details as rd ON mr.building = rd.building
WHERE rd.floor = '1st' and rd.flate_no='C-101'