如何在javascript中减少和过滤数组？

Question

所以我想按照以下方式过滤我的数组：

让我说(ns simple.strings (:require [clojure.string :as str])) (str/starts-with? "hello, world" "hello") ; true

我的数据数组=

array1 = ['c', 'd']

我想过滤掉我的数据数组，以便只有数据数组中的那些对象存在于array1中的userid值。

预期结果：

[{
    "userid": "a",
    "age": 19,
    "name": "john"
}, {
    "userid": "c",
    "age": 119,
    "name": "joy"
}, {
    "userid": "d",
    "age": 119,
    "name": "jesse"
}]

Answer 1

为了让您更好地理解，添加Tushar的解决方案，而不使用lambda表达式，

newDataArray = dataArray.filter(function(item) {return array1.includes(item.userid)})

在ES5中：

var newDataArray = dataArray.filter(function (item) {
    return array1.indexOf(item.userid) !== -1;
});

Answer 2

var a1 = [
    {
        "userid": "a",
        "age": 19,
        "name": "john"
    },
    {
        "userid": "c",
        "age": 119,
        "name": "joy"
    },
    {
        "userid": "d",
        "age": 119,
        "name": "jesse"
    }
];

var a2 = ['c','d'];


var newObj = [];

a1.filter(function(object,index){
    var x = object.userid;
    a2.filter(function(userId){
    if(x==userId){
      newObj[index-1] = object;
    }  
   });
});

console.log(JSON.stringify(newObj));