提交mailchimp subscribe php后我有一个空白页面

时间:2016-02-16 21:28:25

标签: javascript php jquery html

我使用bellow html代码使用mailchimp API在我的mailchimp帐户列表中提交用户电子邮件。

表格代码:

    .....

    <form id="signup-form" action="php/newsletter-subscribe.php" method="post">
        <input type="email" name="email" id="email" placeholder="Email Address" />
        <br>
        <input type="submit" value="Go!" onclick="wating()" />
    </form>

    ......

newsletter-subscribe PHP代码:

require_once 'mailchimp/MailChimp.php';
use \DrewM\MailChimp\MailChimp;

// Email address verification
function isEmail($email) {
    return filter_var($email, FILTER_VALIDATE_EMAIL);
}

if($_POST) {
    $mailchimp_api_key = 'xxxxxxxxxxxxxxxxxxxxx-xx'; // enter your MailChimp API Key
    $mailchimp_list_id = 'xxxxxxxxxx'; // enter your MailChimp List ID

    $subscriber_email = addslashes( trim( $_POST['email'] ) );
    if( !isEmail($subscriber_email) ) {
        echo '<script type="text/javascript">swal("Error!", "Please try again.", "error")</script>';
    } else {
        $array = array();
        $MailChimp = new MailChimp($mailchimp_api_key);
        $result = $MailChimp->post("lists/$mailchimp_list_id/members", [
            'email_address' => $subscriber_email,
            'status'        => 'subscribed',
        ]);

        if($result == false) {
            $array = '<script type="text/javascript">swal("Error!", "Please try again.", "error")</script>';
        } else {
            $array = '<script type="text/javascript">swal("Great!", "Your email has been subscribed", "success")</script>';
        }
        echo json_encode($array);
    }
}

问题是在我提交表单后我得到空白页而没有任何错误日志,并且电子邮件已添加到我的mailchimp帐户而没有任何错误。

我尝试使用echo javascript in line 22, 35 and 38之类的其他java脚本警报更改alert("Text Here");,除了我得到同样的内容空白页

如何解决此问题并在同一html表单页面中回显javascript警报而不重定向到空白页?

1 个答案:

答案 0 :(得分:1)

首先你要设置:

$array = array();

但是稍后,你会这样做:

    if($result == false) {
        $array = '<script type="text/javascript">swal("Error!", "Please try again.", "error")</script>';
    } else {
        $array = '<script type="text/javascript">swal("Great!", "Your email has been subscribed", "success")</script>';
    }
    echo json_encode($array);

换句话说,您正在将数组更改为字符串。 尝试将代码更改为:

    if($result == false) {
        $array = array('<script type="text/javascript">swal("Error!", "Please try again.", "error")</script>');
    } else {
        $array = array('<script type="text/javascript">swal("Great!", "Your email has been subscribed", "success")</script>');
    }
    echo json_encode($array);

另外,我会避免在那里使用<script type="text/javascript">,我只会返回一个正确的json响应。然后,使用ajax(jquery)调用此文件,解码json并显示警报。

也许这样的事情会给你一个想法: http://labs.jonsuh.com/jquery-ajax-php-json/