Question

如果存在第一个字段（主键）或在mysql中插入新行（在单个查询中），如何更新第二个字段？

INSERT INTO employee_lu(employeeId, employee_dept,CREATED_TS) 
SELECT * FROM (SELECT "E1" AS cd, "DGSDFGSF" AS dept, NOW() AS created_ts) AS temp
WHERE NOT EXISTS (SELECT 1 FROM employee_lu WHERE employeeId = "E1" and employee_dept = "DGSDFGSF")LIMIT 1
or if exists (SELECT 1 FROM employee_lu WHERE employeeId = "E1" )LIMIT 1
update employee_lu set employee_dept = "CCCC" WHERE employeeId = "E1"

如果员工身份和给定部门都存在，则不做任何事情。如果员工ID与不同的部门存在，则用新部门（给定）更新旧部门。如果两者都不存在则插入新行。

有人可以告诉我如何在单个查询中执行此操作？如果我只是插入但没有工作，如果添加更新，它工作正常。

只需插入=

INSERT INTO employee_lu(employeeId, employee_dept,CREATED_TS) 
            SELECT * FROM (SELECT "F1" AS cd, "DGSDFGSF" AS description, NOW() AS created_ts) AS temp
        WHERE NOT EXISTS (SELECT 1 FROM employee_lu WHERE employeeId = "F1" and employee_dept = "DGSDFGSF")LIMIT 1;

但是我需要更新该字段是否与我们正在搜索的字段具有不同的值。有人可以告诉我该怎么做。

我的表格如下：

CREATE TABLE `employee_lu` (
  `employeeId` varchar(10) NOT NULL DEFAULT '',
  `employee_dept` varchar(256) NOT NULL DEFAULT '',
  `CREATED_TS` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
  `LAST_UPDATED_TS` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  PRIMARY KEY (`employeeId`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

如何更改列值（如果存在）或插入新列 - Mysql

0 个答案: