Question

基本的SQL问题，但我有一个空白。我有一个表格，其中包含以下设置：

date          eventType
-----------------------
01/01/2016    0
02/01/2016    0
03/01/2016    2
03/01/2016    2
04/01/2016    6
04/01/2016    6
04/01/2016    6
04/01/2016    6
05/01/2016    0
06/01/2016    ...

我想返回＆＃34;下一组事件，其中eventType＆lt;＆gt; 0＆＃34;

所以，如果＆＃34;今天＆＃34;是01/01/2016，查询将返回：

03/01/2016      2
03/01/2016      2

如果＆＃34;今天＆＃34;是03/01/2016，查询将返回：

04/01/2016      6
04/01/2016      6
04/01/2016      6
04/01/2016      6

等

非常感谢

Answer 1

嗯。我认为这可能比看起来有点棘手。这样做可以满足问题中的数据：

select e.*
from events e cross join
     (select top 1 eventType
      from events
      where date > getdate() and eventType <> 0
      order by date
     ) as nexte
where e.date > getdate() and
      e.eventType = nexte.eventType;

或者，或许更合适：

select e.*
from events e cross join
     (select top (1) e.*
      from events
      where date > getdate() and eventType <> 0
      order by date
     ) as nexte
where e.date > nexte.date and
      e.eventType = nexte.eventType;

或者更简单：

select top (1) with ties e.*
from events e
where date > getdate() and eventType <> 0
order by date, eventType

Answer 2

也许这会奏效：

SELECT eventDate, event 
FROM events
WHERE eventDayte > GETDATE()+1 -- limit here to datePart date to avoid confusion with time as this can lead to issues
-- we should provide limit here to avoid return all future events 
AND eventDate <= GETDATE()+2
AND eventType<>0

Answer 3

我有一个不同的解决方案，请检查：

DECLARE @dtEventType DATE = '20160101'

DECLARE @table TABLE ( cDate DATE , eventType TINYINT )

INSERT INTO @table
VALUES( '20160101' , 0 ) 
, ( '20160102' , 0 )
, ( '20160103' , 2 )
, ( '20160103' , 2 )
, ( '20160104' , 6 )
, ( '20160104' , 6 )
, ( '20160104' , 6 )
, ( '20160104' , 6 )
, ( '20160105' , 0 )

SELECT * 
FROM @table L
WHERE cDate = ( 
    SELECT MIN( cDate ) AS mnDate
    FROM @table
    WHERE eventType <> 0
    AND cDate > @dtEventType
)

但我喜欢@ GordonLiff的第三个解决方案。

SQL Server查询返回带有事件的下一个日期

3 个答案: