Question

我正在寻找构建java对象

<placement_rules>
  <section name="news">
    <front_order>
       <article_type name="article1"></article_type>
       <article_type name="article2"></article_type>
    </front_order>
    <back_order>
       <article_type name="article3"></article_type>
    </back_order>
  </section>
  <section name="sports">
    <front_order>
      <article_type name="article4"></article_type>
    </front_order>
    <back_order>
      <article_type name="article5"></article_type>
      <article_type name="article6"></article_type>
    </back_order>
  </section>
</placement_rules>

我需要创建哪些对象？

我从SectionRule.java里面开始

@XStreamAsAttribute
@XStreamAlias("name")
private String sectionName;

@XStreamAlias("front_order")
private List<ConfigPlacementNode> frontOrder = new ArrayList<ConfigPlacementNode>(0);

@XStreamAlias("back_order")
private List<ConfigPlacementNode> backOrder = new ArrayList<ConfigPlacementNode>(0);

如何在其周围创建其他第一类对象？任何帮助将受到高度赞赏。

此致阿玛尔

Answer 1

我从未使用过XStream，但可以使用以下对象模型来表示XML文档。我已经包含了标准的JAXB注释（包含在Java SE 6中）来演示XML mappping。

<强> PlacementRules

import java.util.List;
import javax.xml.bind.*;

@XmlRootElement(name="placement_rules")
@XmlAccessorType(XmlAccessType.FIELD)
public class PlacementRules {

    private List<Section> section;

}

栏目

import java.util.List; import javax.xml.bind.annotation.*; @XmlAccessorType(XmlAccessType.FIELD) public class Section { @XmlAttribute private String name; @XmlElementWrapper(name="front_order") @XmlElement(name="article_type") private List<Article> frontOrderArticles; @XmlElementWrapper(name="back_order") @XmlElement(name="article_type") private List<Article> backOrderArticles; }

<强>文章

import javax.xml.bind.annotation.*; @XmlAccessorType(XmlAccessType.FIELD) public class Article { @XmlAttribute private String name; }

下面是一个示例程序，用于演示它的工作原理：

import java.io.File; import javax.xml.bind.*; public class Demo { public static void main(String[] args) throws Exception { JAXBContext context = JAXBContext.newInstance(PlacementRules.class); Unmarshaller unmarshaller = context.createUnmarshaller(); File xml = new File("src/forum38/input.xml"); PlacementRules placementRules = (PlacementRules) unmarshaller.unmarshal(xml); Marshaller marshaller = context.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); marshaller.marshal(placementRules, System.out); } }

Xstream问题和java对象

1 个答案: