我制作了一个将数据发送到webhost的Android应用程序。我在我的应用程序的登录部分遇到了麻烦。当我还在使用localhost时，一切似乎都能正常工作。然后我将所有的php文件转移到了webhost。
当我运行 LoginActivity.java 时，它给了我这个错误：
致命错误：在 /home/u186950481/public_html/android_login_api/include/DB_Functions.php 的行调用未定义的方法mysqli_stmt :: get_result（） 59
这是我的 DB_Functions.php 代码：
<?php
class DB_Functions {
private $conn;
// constructor
function __construct() {
require_once 'DB_Connect.php';
// connecting to database
$db = new Db_Connect();
$this->conn = $db->connect();
}
// destructor
function __destruct() {
}
/**
* Storing new user
* returns user details
*/
public function storeUser($name, $email, $password) {
$uuid = uniqid('', true);
$hash = $this->hashSSHA($password);
$encrypted_password = $hash["encrypted"]; // encrypted password
$salt = $hash["salt"]; // salt
$stmt = $this->conn->prepare("INSERT INTO users(unique_id, name, email, encrypted_password, salt, created_at) VALUES(?, ?, ?, ?, ?, NOW())");
$stmt->bind_param("sssss", $uuid, $name, $email, $encrypted_password, $salt);
$result = $stmt->execute();
$stmt->close();
// check for successful store
if ($result) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE email = ?");
$stmt->bind_param("s", $email);
$stmt->execute();
$user = $stmt->get_result()->fetch_assoc();
$stmt->close();
return $user;
} else {
return false;
}
}
/**
* Get user by email and password
*/
public function getUserByEmailAndPassword($email, $password) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE email = ?");
$stmt->bind_param("s", $email);
if ($stmt->execute()) {
$user = $stmt->get_result()->fetch_assoc();
$stmt->close();
return $user;
} else {
return NULL;
}
}
/**
* Check user is existed or not
*/
public function isUserExisted($email) {
$stmt = $this->conn->prepare("SELECT email from users WHERE email = ?");
$stmt->bind_param("s", $email);
$stmt->execute();
$stmt->store_result();
if ($stmt->num_rows > 0) {
// user existed
$stmt->close();
return true;
} else {
// user not existed
$stmt->close();
return false;
}
}
/**
* Encrypting password
* @param password
* returns salt and encrypted password
*/
public function hashSSHA($password) {
$salt = sha1(rand());
$salt = substr($salt, 0, 10);
$encrypted = base64_encode(sha1($password . $salt, true) . $salt);
$hash = array("salt" => $salt, "encrypted" => $encrypted);
return $hash;
}
/**
* Decrypting password
* @param salt, password
* returns hash string
*/
public function checkhashSSHA($salt, $password) {
$hash = base64_encode(sha1($password . $salt, true) . $salt);
return $hash;
}
}
?>
为什么这个方法mysqli_stmt::get_result()未定义？我错过了什么吗？我在使用WAMP的本地主机上没有收到此错误。
答案 0 :(得分：0)