使用LLVM LibFuzzer时，'fsantize-coverage = edge'中的值'edge'无效

Question

http://llvm.org/docs/LibFuzzer.html 我现在正在与libfuzzer合作，但是当我使用官方玩具示例时。当我运行此命令时：

clang++ -fsanitize=address -fsanitize-coverage=edge test-fuzzer.cc Fuzzer*.o

发生错误

clang: error: invalid value 'edge' in 'fsanitize-coverage=edge'

似乎clang支持这个论点，但我想知道我怎么能看到支持的价值...... 我用apt-get和unbuntu14.04安装llvm 3.6 ......

Answer 1

fsanitize-coverage=标志的语法已更改，如2015年5月this commit message中所述。此位与您特别相关：

Original semantics of -fsanitize-coverage flag is preserved:
  * -fsanitize-coverage=0 disables the coverage
  * -fsanitize-coverage=1 is a synonym for -fsanitize-coverage=func
  * -fsanitize-coverage=2 is a synonym for -fsanitize-coverage=bb
  * -fsanitize-coverage=3 is a synonym for -fsanitize-coverage=edge
  * -fsanitize-coverage=4 is a synonym for -fsanitize-coverage=edge,indirect-calls

所以你可以试试-fsanitize-coverage=3。