Question

我正在使用对象数组绘制图表。但我没有得到任何输出。我也收到错误Uncaught TypeError: string.slice is not a function - 但我不知道这个问题出在哪里。

任何人都可以帮我解决这个问题吗？

这是我的代码和演示：

window.onload = function () {

var data = [
{"date":20111001,"New York" : 63.4, "San Franscisco" : 62.7, "Austin" : 72.2 },
{"date":20111002,"New York" : 58.0, "San Franscisco" : 59.9, "Austin" : 67.7 },
{"date":20111003,"New York" : 53.3, "San Franscisco" : 59.1, "Austin" : 69.4 },
{"date":20111004,"New York" : 55.7, "San Franscisco" : 58.8, "Austin" : 68.0 },
{"date":20111005,"New York" : 64.2, "San Franscisco" : 58.7, "Austin" : 72.4 },
{"date":20111006,"New York" : 58.8, "San Franscisco" : 57.0, "Austin" : 77.0 },
{"date":20111007,"New York" : 57.9, "San Franscisco" : 56.7, "Austin" : 82.3 },
{"date":20111008,"New York" : 61.8, "San Franscisco" : 56.8, "Austin" : 78.9 },
{"date":20111009,"New York" : 69.3, "San Franscisco" : 56.7, "Austin" : 68.8 },
{"date":20111010,"New York" : 71.2, "San Franscisco" : 60.1, "Austin" : 68.7 }

]

  var margin = {top: 20, right: 80, bottom: 30, left: 50},
    width = 960 - margin.left - margin.right,
    height = 500 - margin.top - margin.bottom;

var parseDate = d3.time.format("%Y%m%d").parse;

var x = d3.time.scale()
    .range([0, width]);

var y = d3.scale.linear()
    .range([height, 0]);

var color = d3.scale.ordinal()
      .domain(["New York", "San Francisco", "Austin"])
      .range(["#FF0000", "#009933" , "#0000FF"]);

var xAxis = d3.svg.axis()
    .scale(x)
    .orient("bottom");

var yAxis = d3.svg.axis()
    .scale(y)
    .orient("left");

var line = d3.svg.line()
    .interpolate("basis")
    .x(function(d) { return x(d.date); })
    .y(function(d) { return y(d.temperature); });

var svg = d3.select("body").append("svg")
    .attr("width", width + margin.left + margin.right)
    .attr("height", height + margin.top + margin.bottom)
  .append("g")
    .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

data.forEach( function ( data, value) {


  color.domain(d3.keys(data[0]).filter(function(key) { return key !== "date"; }));

  data.date = parseDate(data.date);

  var cities = color.domain().map(function(name) {
    return {
      name: name,
      values: data.map(function(d) {
        return {date: data.date, temperature: +data[name]};
      })
    };
  });

  x.domain(d3.extent(data, function(d) { return d.date; }));

  y.domain([
    d3.min(cities, function(c) { return d3.min(c.values, function(v) { return v.temperature; }); }),
    d3.max(cities, function(c) { return d3.max(c.values, function(v) { return v.temperature; }); })
  ]);

  svg.append("g")
      .attr("class", "x axis")
      .attr("transform", "translate(0," + height + ")")
      .call(xAxis);

  svg.append("g")
      .attr("class", "y axis")
      .call(yAxis)
    .append("text")
      .attr("transform", "rotate(-90)")
      .attr("y", 6)
      .attr("dy", ".71em")
      .style("text-anchor", "end")
      .text("Temperature (ºF)");


  var city = svg.selectAll(".city")
      .data(cities)
    .enter().append("g")
      .attr("class", "city");

  city.append("path")
      .attr("class", "line")
      .attr("d", function(d) { return line(d.values); })
      .style("stroke", function(d) { return color(d.name); });

  city.append("text")
      .datum(function(d) { return {name: d.name, value: d.values[d.values.length - 1]}; })
      .attr("transform", function(d) { return "translate(" + x(d.value.date) + "," + y(d.value.temperature) + ")"; })
      .attr("x", 3)
      .attr("dy", ".35em")
      .text(function(d) { return d.name; });

})

}

Live Demo

Answer 1

错误是因为

在您传递的数据中

{"date":20111001,"New York" : 63.4, "San Franscisco" : 62.7, "Austin" : 72.2 },

请在此注明日期，您将日期作为数字示例： 20111001

因此，当您将其解析为Date对象时，您应该将其转换为字符串。

data.date = parseDate(data.date + "");

工作代码here

修改

其他问题是你在for循环中做了不相关的事情。

for循环仅用于将数字日期转换为日期对象，如下所示：

datas.forEach( function ( data, value) { data.date = parseDate(data.date + ""); })

工作代码here

d3js - 我的线图不起作用，并抛出错误

1 个答案: