java.lang.ClassCastException:com.google.gson.internal.LinkedTreeMap无法强制转换为asd.Grade

时间:2016-02-16 11:26:23

标签: java gson

我手中有一个大型项目,但我在这个例子中模拟了我正在努力解决的问题:

我的第一堂课:

package asd;

import java.io.Serializable;

public class Grade implements Serializable{
String name;
Integer score;

public String getName() {
    return name;
}

public Grade() {}

public Grade(String name, Integer score) {
    this.name = name;
    this.score = score;
}

public void setName(String name) {
    this.name = name;
}

public Integer getScore() {
    return score;
}

public void setScore(Integer score) {
    this.score = score;
}
}

我的第二堂课:

package asd;

import java.io.Serializable;


public class Student implements Serializable {
private String name;
private Object grade;

public String getName() {
    return name;
}

public Student(String name, Object grade) {
    this.name = name;
    Grade = grade;
}

public Student() {}

public void setName(String name) {
    this.name = name;
}

public Object getGrade() {
    return Grade;
}

public void setGrade(Object grade) {
    Grade = grade;
}
}

这是我的主要课程:

package asd;

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;

import java.io.*;

public class Test {
public static void main(String[] args){
    Student s1 = new Student();
    s1.setName("JeanPierre");
    s1.setGrade(new Grade("Math", 8));

    Gson gson = new GsonBuilder().create();
    String convertedToJson = gson.toJson(s1);
    System.out.println("Json string: " + convertedToJson);

    Student s2 = gson.fromJson(convertedToJson, Student.class);

    System.out.println("Student Name: " + s2.getName());
    System.out.println("Grade Name: " + ((Grade)s2.getGrade()).getName());
    System.out.println("Grade Score: " + ((Grade)s2.getGrade()).getScore());

}
}

输出:

Json字符串是:

{"name":"JeanPierre","Grade":{"name":"Math","score":8}}

Student Name: JeanPierre


Exception in thread "main" java.lang.ClassCastException: com.google.gson.internal.LinkedTreeMap cannot be cast to asd.Grade
    at asd.Test.main(Test.java:24)

我的问题是我打电话的时候:

System.out.println("Grade Name: " + ((Grade)s2.getGrade()).getName());

System.out.println("Grade Score: " + ((Grade)s2.getGrade()).getScore());

我得到了这个例外:

Exception in thread "main" java.lang.ClassCastException: com.google.gson.internal.LinkedTreeMap cannot be cast to asd.Grade
    at asd.Test.main(Test.java:24)

3 个答案:

答案 0 :(得分:1)

GradeStudent的声明和设置在语法上是错误的。不确定它是如何构建的那样。

public class Student implements Serializable
{
    protected String name ;
    protected Grade grade ;

    public Student( String name, Grade grade )
    {
       this.setName(name).setGrade(grade) ;
    }

    public String getName()
    { return this.name ; }

    public Student setName( String name )
    {
        this.name = name ;
        return this ;
    }

    public Grade getGrade()
    { return this.grade ; }

    public Student setGrade( Grade grade )
    {
        this.grade = grade ;
        return this ;
    }
}

答案 1 :(得分:0)

您还需要解析成绩课程。它不会在一次尝试中转换整个复杂对象。请尝试以下代码:

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;

public class Test {
public static void main(String[] args){
    Student s1 = new Student();
    s1.setName("JeanPierre");
    s1.setGrade(new Grade("Math", 8));

    Gson gson = new GsonBuilder().create();
    String convertedToJson = gson.toJson(s1);
    System.out.println("Json string: " + convertedToJson);

    Student s2 = gson.fromJson(convertedToJson, Student.class);

    System.out.println("Student Name: " + s2.getName());

    Grade g = gson.fromJson(s2.getGrade().toString(), Grade.class);
    System.out.println("Grade Name: " + g.getName());
    System.out.println("Grade Score: " + g.getScore());

}
}

此处s2.getGrade().toString()仍然是有效的JSON字符串。您正在将其转换为Grade类并使用它。这是解析复杂对象的正确方法。希望你能理解。

答案 2 :(得分:0)

我将所有内容更改为XML并立即使用XStream,这适用于我的测试。感谢大家的回答。