Question

我试图插入Integer值但它不能接受这些值。取第二个String值并给出数据类型的异常

这是我的插入代码

void addCategory(Category Category) {
    SQLiteDatabase db = this.getWritableDatabase();

    ContentValues values = new ContentValues();
    values.put(KEY_IMG, Category.getimg()); // Category Name
    values.put(KEY_NAME, Category.getName()); // Category Name
    values.put(KEY_SELECTION, Category.isSelected()); // Category Phone

    // Inserting Row
    db.insert(TABLE_CategoryS, null, values);
    db.close(); // Closing database connection
}

这是选择代码

public List<Category> getAllCategorys() {
    List<Category> CategoryList = new ArrayList<Category>();
    // Select All Query
    String selectQuery = "SELECT  * FROM " + TABLE_CategoryS;

    SQLiteDatabase db = this.getWritableDatabase();
    Cursor cursor = db.rawQuery(selectQuery, null);

    // looping through all rows and adding to list
    if (cursor.moveToNext()) {
        do {
            Category Category = new Category();
            Category.setID(Integer.parseInt(cursor.getString(0)));
            Category.setimg(Integer.parseInt(cursor.getString(1)));
            Category.setName(cursor.getString(2));
            Category.setSelected(cursor.getString(3));
            CategoryList.add(Category);
        } while (cursor.moveToNext());
    }

    // return Category list
    return CategoryList;
}

这是价值观

db.addCategory(new Category(R.drawable.angle, "Angle", "true"));
db.addCategory(new Category(R.drawable.angle, "Area", "true"));
db.addCategory(new Category(R.drawable.angle,"Currency", "true"));
db.addCategory(new Category(R.drawable.angle,"Current", "true"));
db.addCategory(new Category(R.drawable.angle,"Density", "true"));
db.addCategory(new Category(R.drawable.angle,"Length", "true"));

这是Logcat错误：

at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:745)
    Caused by: java.lang.NumberFormatException: Invalid int: "Angle"
at java.lang.Integer.invalidInt(Integer.java:138)
at java.lang.Integer.parse(Integer.java:410)

它无法获取int值。它向上移动到角度＆＃34;值

这是我的创建表查询

public void onCreate(SQLiteDatabase db) {
    String CREATE_CategoryS_TABLE = "CREATE TABLE " + TABLE_CategoryS + "("
        + KEY_ID + " INTEGER PRIMARY KEY," + KEY_IMG + "INTEGER," +
        KEY_NAME + " TEXT," + KEY_SELECTION + " TEXT"  + ")";
    db.execSQL(CREATE_CategoryS_TABLE);
}

这是我的分类：

public class Category 
{
    int id;
    int img;
    String name = null;
    String selected = "true";
    public Category()
    {

    }

    public Category(int img, String name, String selected) {

        this.name = name;
        this.selected = selected;
        this.img = img;
    }
    public Category(int id,int img, String name, String selected) {

        this.id = id;
        this.name = name;
        this.selected = selected;
        this.img = img;
    }

    public int getID() { return id; }

    public void setID(int id) {
        this.id = id;
    }

    public int getimg() { return img; }

    public void setimg(int img) {
        this.img = img;
    }

    public String getName() { return name; }

    public void setName(String name) {
        this.name = name;
    }

    public String isSelected() {
        return selected;
    }

    public void setSelected(String selected) {
        this.selected = selected;
    }
}

Answer 1

更改代码中的行 -

Object

到 -

Category.setID(Integer.parseInt(cursor.getString(0)));
Category.setimg(Integer.parseInt(cursor.getString(1)));

更改您的创建表查询，如下所示 -

Category.setID(cursor.getInt(0));
Category.setimg(cursor.getInt(1));

Answer 2

如果修改数据库的表，则必须更改数据库的版本，或者可以卸载并重新安装应用程序。从光标读取时，在遍历游标之前始终使用cursor.movetoFirst。

在Sqlite android中插入Integer Value

2 个答案: