Question

提示用户输入数组的大小并允许用户访问输入整数值到您的数组。检查每个元素是否均匀或奇怪的。如果是偶数，打印解决了elemets（升序），如果奇数，得到使用条件语句的最大值和最小值。输出结果。

public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);
    System.out.println("Enter a number: ");
    int n = sc.nextInt();
    int s[] = new int[n];
    for (int i = 0; i < n; i++) {
        int e = sc.nextInt();
        s[i] = e;
    }

    Arrays.sort(s);
    System.out.println("\nEven numbers in ascending order:");
    for (int j = 0; j < n; j++) {

        if (s[j] % 2 == 0) {
            System.out.print(s[j] + " ");
        }
    }

    System.out.println("\nOdd numbers in descending order:");
    for(int j = (n -1); j >= 0; j--) {
        if (s[j] % 2 == 1) {
            System.out.print(s[j] + " ");
        }
    }
}

我不知道如何为Odd

添加min / max

Answer 1

如果我理解你的问题，你可以试试这个：

int min = Integer.MAX_VALUE; // init min to the most max value
int max = 0; // store max value
for(int j = (n -1); j >= 0; j--) {
    if (s[j] % 2 == 1) {
        if (min > s[j]) {
            min = s[j];
        }
        if (max < s[j]) {
            max = s[j];
        }
        System.out.print(s[j] + " ");
    }
}
System.out.println("min = " + min);
System.out.println("max = " + max);

完整代码：

public static void main(String[] args) throws Exception {
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter a number: ");
    int n = sc.nextInt();
    int s[] = new int[n];
    for (int i = 0; i < n; i++) {
        int e = sc.nextInt();
        s[i] = e;
    }

    Arrays.sort(s);
    System.out.println("\nEven numbers in ascending order:");
    for (int j = 0; j < n; j++) {

        if (s[j] % 2 == 0) {
            System.out.print(s[j] + " ");
        }
    }

    //===========================================
    System.out.println("\nOdd numbers in descending order:");
    int min = Integer.MAX_VALUE; // init min to the most max value
    int max = 0; // store max value
    for(int j = (n -1); j >= 0; j--) {
        if (s[j] % 2 == 1) {
            if (min > s[j]) {
                min = s[j];
            }
            if (max < s[j]) {
                max = s[j];
            }
            System.out.print(s[j] + " ");
        }
    }
    System.out.println(); // for new line
    System.out.println("min = " + min);
    System.out.println("max = " + max);
}

Answer 2

我的问题的解决方案是：

Scanner sc = new Scanner(System.in);
while (true) {
  System.out.print("Enter a Value: ");
  int val = s.nextInt();

  if (val == 0) {
      break;
  }
  if (val < min) {
      min = val;
  }
  if (val > max) {
     max = val;
  }
}

System.out.println("min: " + min);
System.out.println("max: " + max);

甚至，Odd只有最小值和最大值

2 个答案: